Question

What is the magnitude of the momentum of

a. A $3000kg$truck traveling at $15m/s$?

b. A $200g$ baseball thrown at $40m/s$?

Short answer

a. $p_{truck}=45\times {10}^{3}kg\times m/s$

b. $p_{baseball}=8kg\times m/s$

Step-by-step solution

Part(a) Step 1: Given information   

We need to find the magnitude of the momentum of a traveling truck.

Part(a) Step 2: Simplify   

Objects with mass $m$and speed $s$have momentum $p$, which is the product of mass and speed. and large momentum consists the large mass or large velocity.the momentum is given by equation in the form

$p=mv\left(1\right)$

$m_{truck}=3000kg$is mass of the truck and velocity is $v_{truck}=15m/s$.To get the momentum of the car using equation $\left(1\right)$and putting the values for $3000kgand15m/s$.

localid="1649419841772" $$\begin{gathered} p_{truck}=m_{truck}{v}_{truck} \\ =(3000kg)(15m/s) \\ =(45\times {10}^{3}kg)\times m/s \end{gathered}$$

Part(b) step 1: Given information  

We need to find the magnitude of the momentum of thrown baseball.

Part(b) Step 2: Simplify   

Mass and velocity of baseball is $m_b=200gand{v}_b=40m/s$. putting the values for $200gand40m/s$into equationlocalid="1649343987210" $\left(1\right)$to get the momentum of baseball by

localid="1649419821356" $$\begin{gathered} p_{baseball}=m_b{v}_b \\ =(200\times {10}^{-3}kg)(40m/s) \\ =8kg\times m/s \end{gathered}$$