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FIGURE EX24.17shows three charges. Draw these charges on your paper four times. Then draw two-dimensional cross sections of three-dimensional closed surfaces through which the electric flux is (a) 2q/ϵ0, (b) q/ϵ0, (c) 0,and (d) 5q/ϵ0.

Short Answer

Expert verified

(a) Draw a closed surface around the charge 2qonly.

(b) Draw a closed surface around the charges 3qand2qonly.

(c) Draw a closed surface around the charges 2qand2qonly.

(d) Draw a closed surface around the charges 3qand2qonly.

Step by step solution

01

Electric Flux

(a) The quantity of energy field that moves through such a solid object is referred to as the induced voltage. The light beam through a plate is proportional to the charge inside the surface, so according Gauss's rule, which is calculated (24.18)in the form

Φe=EdA=Qinϵo

The electric rate is driven by the charge from the inside of the closed surface, as depicted. Because every flux related to charges outside the closed surface is zero, we form a closed area around the number of charges the flux equals to obtain the fluxes.

To design a closed field, the zeta potential must be sketched in a same method. We draw a closed surface it around surface ions of intensity 2qonly for a flow of 2q/ϵor, as seen below.

02

Net Charge

(b) We design a complete area around total costs of qfor a flux of q/ϵor. This may transpire if the dual penalties 3qand2qare mixed, so we draw a flat sphere above it parameters.

03

Net Charges Zero

(c) We design a complete area around total costs of 0for a flux of 0. This may transpire if the dual penalties 2qand2qare mixed, so we draw a flat sphere above it parameters.

04

Net Charge Five

(d) We design a complete area around total costs of 5qfor a flux of 5q/ϵoThis may transpire if the dual penalties 3qand2qare mixed, so we draw a flat sphere above it parameters.

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Most popular questions from this chapter

II An infinite slab of charge of thickness 2z0lies in the XYplane between z=z0andz=+z0. The volume charge density ρC/m3is a constant.

a. Use Gauss's law to find an expression for the electric field strength inside the slab z0zz0.

b. Find an expression for the electric field strength above the slab zz0.

c. Draw a graph of Efrom z=0toz=3z0.

FIGUREEX24.18shows three charges. Draw these charges on your paper four times. Then draw two-dimensional cross sections of three-dimensional closed surfaces through which the electric flux is (a) -q/ϵ0, (b) q/ϵ0, (c) 3q/ϵ0, and (d) 4q/ϵ0.

A positive point chargeq sits at the center of a hollow spherical shell. The shell, with radius R and negligible thickness, has net charge -2q. Find an expression for the electric field strength (a) inside the sphere, r<K, and (b) outside the sphere, r>K. In what direction does the electric field point in each case?

A tetrahedron has an equilateral triangle base with20-cm-long edges and three equilateral triangle sides. The base is parallel to the ground, and a vertical uniform electric field of strength 200N/C passes upward through the tetrahedron. a. What is the electric flux through the base? b. What is the electric flux through each of the three sides?

A spherical shell has inner radius Rinand outer radius Rout. The shell contains total charge Q, uniformly distributed. The interior of the shell is empty of charge and matter.

a. Find the electric field strength outside the shell,rRout .

b. Find the electric field strength in the interior of the shell, rRin.

c. Find the electric field strength within the shell, RinrRout.

d. Show that your solutions match at both the inner and outer boundaries

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