Question

For the circuit shown in FIGURE $P28.60$, find the current through and the potential difference across each resistor. Place your results in a table for ease of reading.

Short answer

We have given that the circuit.

We need to find the current through and potential difference across each resistor.

Step-by-step solution

Given information

We have given that the circuit.

We need to find the current through and potential difference across each resistor.

Simplify

The given circuit could be simplified to be drawn as shown in the figure below. If we have two points and there resistors connected at both ends of the points, we called that the resistors are connected in parallel connection. Equation $(28.24)$shows the equivalent resistance for the parallel connection in the form

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_N}$ $\left(1\right)$

The three resistors $4\Omega ,48\Omega$and $16\Omega$are in parallel, so we use equation $\left(1\right)$to get their combination by

$$\begin{gathered} \frac{1}{R_{1,eq}}=\frac{1}{4\Omega }+\frac{1}{16\Omega }+\frac{1}{48\Omega } \\ {R}_{1,eq}=\frac{1}{4\Omega }+\frac{1}{16\Omega }+{\frac{1}{48\Omega }}^{-1} \\ {R}_{1,eq}=3\Omega \end{gathered}$$

Simplify

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