Question

What is the current in the$2\Omega$resistor in FIGURE P28.53?

Short answer

The current will be$3\mathrm{A}.$

Step-by-step solution

Given information

We have given,

resistances = $2\Omega ,4\Omega$

Voltage supply = $9\mathrm{V},3\mathrm{V}$

We have to find the current across $2\Omega$.

Simplify

Using Kirchhoff voltage rule and let current flowing in the circuit is I.

$$\begin{gathered} \sum _{\mathrm{i}}V=0 \\ -9\mathrm{V}+3\mathrm{V}+2\Omega \times \mathrm{I}=0 \\ \mathrm{I}=\frac{6}{2} \\ \mathrm{I}=3\mathrm{A} \end{gathered}$$