Question

The tip of a flashlight bulb is touching the top of the $3V$battery in FIGURE Q28.2. Does the bulb light? Why or why not?

Short answer

The circuit is open, thus it doesn't work.

Step-by-step solution

Given information and formula used

Given :

Volt of battery the tip of the flashlight bulb is touching : $3V$

Theory used :

Potential difference between any two points is defined as the amount of work done in moving a unit charge from one point to another.

$dv=\frac{dw}{dq}$

Determining if the bulb lights

There is a potential difference between the terminals of the battery. When a wire or resistance is connected between two terminals, current finds a way to flow from one to the other. Because the light bulb is linked to only one contact, the circuit cannot be closed to allow current to flow, and the bulb will not light.

As a result, the answer is that it does not light.