Question

I A potential difference of $0.050\text{V}$is developed across the localid="1650925760420" $10-\text{cm}$long wire of FIGURE EX30.2 as it moves through a magnetic field perpendicular to the page. What are the strength and direction(in or out) of the magnetic field?

Short answer

The strength of magnetic field is$0.10\text{T}$ , and the direction is inside the page.

Step-by-step solution

Step 1. Given information

Potential difference$e=0.05\text{V}$

Length of wire$=10\text{cm}=0.1\text{m}$

Speed$\left(\text{v}\right)=5.0\text{m}/\text{s}$

Magnetic field is perpendicular to the page.

Step 2. Explanation

The potential difference is calculated using the formula

$\begin{array}{l}e=lvB\\ 0.05=5\times 0.1\times B\\ B=0.1\text{T}\end{array}$

To direction of magnetic field has been calculated by the right-hand thumb rule. The positive charge, given in figure, experienced a magnetic force in left direction. The velocity is in upward direction; therefore, by right hand thumb rule, we find that magnetic field direction is inside the page.

The strength of magnetic field is $0.10\text{T}$, and the direction is inside the page.