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The metal wire in FIGURE moves with speed vparallel to a straight wire that is carrying current I. The distance between the two wires isd. Find an expression for the potential difference between the two ends of the moving wire.


Short Answer

Expert verified

Potential Difference between two ends,ฮต=ฮผoIv2ฯ€1+ld

Step by step solution

01

Introduction

A field of force is generated by a current-carrying wire, and the Biot-Savart law allows us to calculate the magnitude and direction of this flux. Any moment the force field varies as a function of the segmentฮ”sโ†’of current-carrying wire is given by equation

B=ฮผo2ฯ€Ix

02

Find the Flux

The induced emf, as per Faraday's law, is the change in magnetic force inside the loop, and it's computed using an equation within the shape.

ฮต=dฮฆmdt

Whereฮฆmis that the flux through the wire which is that the quantity of magnetic flux that flows through a wire of area Aand it's given by

dฮฆm=d(BA)=BdA

=ฮผo2ฯ€Ix(Ldx)

=ฮผ0L2ฯ€Ixdx

The flux changes from point x=dto point x=d+lwherelis the length of the wire. So, we integrate the flux by

โˆซdฮฆm=ฮผoLI2ฯ€โˆซdd+l1xdx

ฮฆm=ฮผoL12ฯ€[lnx]dd+l

ฮฆm=ฮผoLI2ฯ€[ln(d+l)-ln(d)]

ฮฆm=ฮผoLI2ฯ€1+ld

03

The voltage difference between two points

Use this expression of ฮฆminto equation to urgeฮตby

ฮต=ddtฮผoLI2ฯ€1+ld

=ฮผ0I2ฯ€1+lddLdt

=ฮผoIv2ฯ€1+ld

Where vis that the speed of the loop

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