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Unpolarized light of intensity I0is incident on a stack of polarizing filters, each with its axis rotated 15˚cwwith respect to the previous filter. What light intensity emerges from the last filter?

Short Answer

Expert verified

The light of filter emerges from the last filter isI7=3.29.

Step by step solution

01

Definition of Electromagnetic fields and Waves:

Electromagnetic waves, or EM waves, are waves that are formed when an electric field and a magnetic field vibrate together. EM waves, in other words, are made up of oscillating magnetic and electric fields.

02

Definition of Light of Intensity:

The strength or amount of light produced by a certain lighting source is referred to as light intensity. It is a measurement of a light source's wavelength-weighted power.

03

We have to find value of intensity emerges from last filters:

Givenvalues:θ=15˚Weknowthat:I1=1/2I0Weuseformula:I2=I1cos2θFrompreviousformula,wehavetofindvalueforI7:First,wefindvalueforI2:I2=I1cos2θI2=102cos215˚I2=5×0.933I2=4.66(Substitutevaluesinequation.)

04

Substitute values in equation:

I3=I2cos2θI3=4.66cos2(15˚)I3=4.66×0.933I3=4.34

05

Next substitution in equation :

I4=I3cos2θI4=4.34cos2(15˚)I4=4.34×0.933I4=4.05

06

Next:

I5=I4cos2θI5=4.05cos2(15˚)I5=4.05×0.933I5=3.78

07

Substitution:

I6=I5cos2θI6=3.78cos2(15˚)I6=3.78×0.933I6=3.53

08

Finally, we calculate for I7:

I7=I6cos2θI7=3.53cos2(15˚)I7=3.53×0.933I7=3.29

09

Final result:

The result for the light of intensity I0is incident on a stack of 7polarizing filters and each axis rotated 15˚cwfrom previous filter to last filter is .

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