Question

What is the electric field amplitude of an electromagnetic wave whose magnetic field amplitude is $2.0\mathrm{mT}$ $?$

Short answer

The electric field amplitude of an electromagnetic wave is$6\times {10}^5\mathrm{V}/\mathrm{m}$.

Step-by-step solution

Formula for electric field amplitude

As it stands,

$\mathrm{B}=2.0\mathrm{mT}$

$\mathrm{c}=3\times {10}^8\mathrm{m}/\mathrm{s}$

Electric field amplitude is,

$\mathrm{E}=\mathrm{B}·\mathrm{c}$

$\mathrm{B}$is magnetic field amplitude.

localid="1648800544485" $\mathrm{c}$is in a vacuum, the speed of light .

Calculation for Electric field amplitude

Electric field amplitude,

$\mathrm{E}=\mathrm{B}·\mathrm{c}$

Substitute all values,

$\mathrm{E}=2.0\times {10}^{-3}\mathrm{T}\times 3\times {10}^8\mathrm{m}/\mathrm{s}$

$\mathrm{E}=6\times {10}^5\mathrm{V}/\mathrm{m}$