Question

The force on the $-1.0$nCcharge is as shown inFIGURE CP22.76.What is the magnitude of this force?

Short answer

The strength of the electric field is$1.44\times {10}^{-3}\mathrm{N}/\mathrm{C}$in the direction of the electron.

Step-by-step solution

Given information

The distance of the field point from the electron is$1.0mm$.

Explanation

In the present case,. the source charge is $\left(q\right)$electron.

role="math" localid="1648483904923" $$\begin{gathered} \overrightarrow{E}=\frac{1}{4\pi {\epsilon }_0}\frac{q}{r^2}\hat{r}\dots \dots \left(1\right) \\ q=-1.6\times {10}^{-19}\mathrm{Cr}=1\times {10}^{-3}\mathrm{m}\overrightarrow{E}=\frac{\left(9\times {10}^9\right)\times 1.6\times {10}^{-19}}{{\left({10}^{-3}\right)}^2}\left(\text{directionistowardstheelectron}\right) \\ \overrightarrow{E}=1.44\times {10}^{-3}\mathrm{N}/\mathrm{C}\left(towardstheelectron\right) \end{gathered}$$