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A rocket-powered hockey puck has a thrust of 2.0N and a total mass of 1.0kg. It is released from rest on a frictionless table, 4.0m from the edge of a 2.0m drop. The front of the rocket is pointed directly toward the edge. How far does the puck land from the base of the table?

Short Answer

Expert verified

The puck will land 2.91maway from the edge of the table.

Step by step solution

01

Given Information 

The mass of the puck is m=1.0kg, the thrust of the puck is F=2.0N, the distance traveled on friction less table is s=4.0m, and the height of the table is h=2.0m, the acceleration due to gravity is g=9.8m.

We have to calculate the landing distance of the puck from the edge of the table.

02

Explanation

The thrust of 2.0Ngives acceleration ato mass m=1.0kg of puck:

a=Fm

=2.01.0

role="math" localid="1648367113682" =2m/s2

Now puck is accelerated with adistance of 4.0m.

The velocity of puck when it is at edge, using third equation of motion:

v2=u2+2as

vis the velocity at any time

uis the initial velocity=0

ais the acceleration

sis the distance travelled=4.0m

vf=2as=2×2×4.0

role="math" localid="1648367610157" vf=4m/s

03

Applying second equation of motion

At the edge, puck with horizontal motion starts vertical motion of falling downward with gravitational acceleration.

Using the second equation of motion:

h=vit+12gt2

where,

h=2.0m

g=9.8m/s2

t2=2hg

t=2hg

t=2×29.8

=0.63s

As puck is accelerated horizontally still witha=2m/s2, it goes distancexin the time0.63s, as it has horizontal velocityvi=4m/sat the edge

Applying second equation of motion again:

x=vit+12at2

x=(4.0×0.63)+12×2×(0.63)2

x=2.91m

So puck only goes 2.91maway from base of the table

04

Final Answer 

The puck only goes2.91maway from the edge of the table

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