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A 50kgbox hangs from a rope. What is the tension in the rope if:

a. The box is at rest?

b. The box moves up at a steady 5.0m/s?

c. The box has vy=5.0m/sand is speeding up at 5.0m/s2?

d. The box has vy=5.0m/s and is slowing down at 5.0m/s2 ?

Short Answer

Expert verified

Rope's tension value when the box is,

(a) at rest,T=490N.

(b) moving with uniform velocity,T=490N.

(c) speeding up,T=740N.

(d) speeding down,T=240N.

Step by step solution

01

Tension :

The pulling force transferred axially by a string, cable, chain, or similar item, or by each end of a rod, truss member, or similar three-dimensional object is known as tension.

02

(a) Explanation :

Newton's first law of motion states that an item remains at rest or in uniform motion until it is acted with by a net external force.

The quantity of force exerted on an object is equal to the product of its mass and the acceleration generated, according to Newton's second equation of motion.

F=ma

In this scenario, the item is a box that is suspended vertically by a rope. The free body diagram of the box is shown below.

T=mg+may

Mass of box m=50kg,

Acceleration due to gravity g=9.8m/s2,

rest velocity vy=0m/s,

acceleration ay=0m/s2.

T=mg+ay

T=509.8+0T=490N

Hence, rope's tension value when the box is at rest is490N.

03

(b) Explanation : 

Mass of box m=50kg,

Acceleration due to gravity g=9.8m/s2,

steady velocity vy=5m/s,

acceleration ay=0m/s2.

Substituting values in equation,

T=mg+ay

T=509.8+0T=490N

Hence, rope's tension value when the box is moving with uniform velocity is490N.

04

(c) Explanation : 

Mass of box m=50kg,

Acceleration due to gravity g=9.8m/s2,

velocity vy=5m/s,

acceleration ay=5m/s2.

Substituting values in equation,

T=mg+ay

T=509.8+5T=740N

Hence, rope's tension value when the box is speeding up is740N.

05

(d) Explanation :

Mass of box m=50kg,

Acceleration due to gravity g=9.8m/s2,

velocity vy=5m/s,

acceleration ay=-5m/s2.

Substituting values in equation,

T=mg+ay

T=509.8-5T=240N

Hence, rope's tension value when the box is speeding down is240N.

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Most popular questions from this chapter

An object moving in a liquid experiences a linear drag force: Fudrag=(bv,direction opposite the motion), where bis a constant called the drag coefficient. For a sphere of radius R,the drag constant can be computed asb=6phR, where his the viscosity of the liquid.

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