Question

Predict the ground-state electron configurations of $Al,Gn$ and $In$?

Short answer

The ground-state electron configurations of $Al$is $1s^{2}2s^{2}2p^{6}3s^{2}3p$, $Gn$is $1s^{2}2s^{2}2p^{6}3s^{2}3p4s^{2}3d^{10}4p$and$In$is$1s^{2}2s^{2}2p^{6}3s^{2}3p4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p$.

Step-by-step solution

Given Information

We need to find the ground-state electron configurations of $Al,Gn$and$In$.

Simplify

The electron configuration for $Al,Gn$and $In$.

First, finding the electron configuration for $Al\left(Z=13\right)$:

$1s^{2}2s^{2}2p^{6}3s^{2}3p$

Total numbers of electron is $\left(2+2+6+2+1=13\right)$.

Now, finding the electron configuration for $Gn\left(Z=31\right)$:

role="math" localid="1650271286398" $1s^{2}2s^{2}2p^{6}3s^{2}3p4s^{2}3d^{10}4p$

Total number of electron is $\left(2+2+6+2+6+2+10+1=31\right)$

At last, finding the electron configuration for role="math" localid="1650271252311" $\ln \left(Z=49\right)$:
$1s^{2}2s^{2}2p^{6}3s^{2}3p4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p$

Total number of electron is $\left(2+2+6+2+6+2+10+6+2+10+1=49\right)$