Question

List the quantum numbers, excluding spin, of

(a) all possible $3p$ states and

(b) all possible $3d$ states.

Short answer

(a) All possible $3p$states are $$\begin{gathered} \frac{nlm}{31+1} \\ 310 \\ 31-1 \end{gathered}$$

(b) All possible $3d$states are$$\begin{gathered} \frac{nlm}{32+2} \\ 32+1 \\ 320 \\ 32-1 \\ 32-2 \end{gathered}$$

Step-by-step solution

Part (a) step 1: Given Information

We need to find the quantum numbers, excluding spin, of all possible $3p$states.

Part (a) step 2: Simplify

We finding all possible $3d$state.

Now, $3p$state is described by $n=3$and $l=1$.

$$\begin{gathered} \frac{nlm}{31+1} \\ 310 \\ 31-1 \end{gathered}$$

Part (b) step 1: Given Information

We need to find the quantum numbers, excluding spin, of all possible $3d$states.

Part (b) step 2: Simplify

We have to find all possible $3d$states.

Then, $3p$the state is described by $n=3$and $l=2$

$$\begin{gathered} \frac{nlm}{32+2} \\ 32+1 \\ 320 \\ 32-1 \\ 32-2 \end{gathered}$$