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A 200 Ω resistor is connected to an AC source with ε0=10 V. What is the peak current through the resistor if the emf frequency is (a) 100 Hz? (b) 100 kHz?

Short Answer

Expert verified

result is:Io=50mA

Step by step solution

01

Part(a) Step 1 : Given information

R=200Ω

εo=10V

Frequency =100Hz

02

Part (a) Step 2: Simplify 

Peak current is given byI=εoR,does not depend upon frequency

Io=εoR

Io=10V200Ω

Io=0.05A50mA

03

Part(b) Step 1 : Given information

R=200Ω

εo=10V

Frequency=100 kHz

04

Part (b) Step 2: Simplify 

Peak current is given by I=εoR,does not depend upon frequency

I0=εoR

Io=10V200Ω

Io=0.05A50mA

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Most popular questions from this chapter

II An electric circuit, whether it's a simple lightbulb or a complex amplifier, has two input terminals that are connected to the two output terminals of the voltage source. The impedance between the two input terminals (often a function of frequency) is the circuit's input impedance. Most circuits are designed to have a large input impedance. To see why, suppose you need to amplify the output of a high-pass filter that is constructed with a 1.2kΩ resistor and a 15μF capacitor. The amplifier you've chosen has a purely resistive input impedance. For a 60Hz signal, what is the ratio VRload/VRno loadof the filter's peak voltage output with (load) and without (no load) the amplifier connected if the amplifier's input impedance is (a) 1.5kΩand (b) 150kΩ ?

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