Question

In the series RLC circuit represented by the phasors of FIGURE Q32.7, is the EMF frequency less than, equal to, or greater than the resonance frequency ${\omega }_0$? Explain.

Short answer

The EMF frequency is less than resonance frequency$\omega <{\omega }_0$

Step-by-step solution

Step 1. Given Information

We have been given that EMF phasor lags behind current phasor

Step 2. Solving

Since the EMF phasor lags behind current phasor it means $V_c>V_l$.

As EMF frequency increases $V_c$decreases and $V_l$increases and at resonance frequency$\left({\omega }_0\right)$${\mathrm{V}}_{\mathrm{c}}={\mathrm{V}}_{\mathrm{l}}$

Since $V_c$is greater than $V_l$we can say that EMF frequency is less than resonance frequency