Question

A $110Hz$source of emf has a peak voltage of $50V$. Draw the emf phasor at $t=3.0ms$.

Short answer

Required emf phasor is:

Step-by-step solution

Given information

We are given that Peak voltage = $50V$,frequency = $110Hz$,$t=3x{10}^{-3}s$

Explanation

We know that $\omega =2\pi f$

$$\begin{gathered} \omega =2\pi \times 110Hz \\ \omega =220\pi rad/s \end{gathered}$$

then, We need to find angle$\theta$

$$\begin{gathered} \theta =\omega t=220\pi \times 3\times {10}^{-3}=0.66\pi \\ \theta =\frac{2}{3}\pi x57.29°(1rad=57.{29}^{\circ }) \\ \theta \simeq {120}^{\circ } \end{gathered}$$