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A diver makes \(2.5\) complete revolutions on the way from a 10 -m platform to the water below. Assuming zero initial vertical velocity, calculate the average angular velocity for this drive.

Short Answer

Expert verified
The average angular velocity is the total angle covered divided by the time taken to cover that angle. Apply the values found in the previous steps into the formula for angular velocity to get the answer.

Step by step solution

01

Calculate Time of Fall

We calculate the time it takes for the diver to fall by using the second equation of motion: \(h=\frac{1}{2}gt^2\), where \(h\) is the height, \(g\) is the gravitational constant 9.8 m/s². So, \(10=\frac{1}{2}*9.8*t^2\) \n Solving this will give us the time of fall.
02

Calculate the total angle of the rotations

We know the diver completes 2.5 revolutions on the way down. Each revolution is \(2\pi\) radians, so the total angle \(a\) that the diver rotates through is \(2.5 * 2\pi\). This gives us the total angle in radians.
03

Calculate Angular Velocity

Finally, we apply the formula for average angular velocity, which is the total angle covered divided by the time taken to cover that angle. We can express average angular velocity (\(\omega\)) as \(\omega = \frac{a}{t}\). By substituting the values of \(a\) and \(t\) from previous steps, we get the average angular velocity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equations of Motion
The equations of motion are indispensable tools in physics, used to predict the final position and velocity of an object moving under constant acceleration. One such equation, relevant to our problem, is given by the formula for displacement under the influence of gravity:
\[ h = \frac{1}{2}gt^2 \]
In this formula, \( h \) stands for the height traveled, \( g \) is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and \( t \) is the time taken to travel that height. To find the stop-watch time of a diver's fall, one can rearrange this equation to solve for \( t \), which is crucial for further calculations involved in determining the diver's average angular velocity.
Angular Displacement
Angular displacement refers to the angle through which a point or line has been rotated in a specified sense about a specified axis. It is the angle of the arc traveled at a radius from the axis of rotation, measured in radians or degrees. For a complete revolution, the angular displacement is \( 2\pi \) radians. Since an object can undergo multiple revolutions, the total angular displacement would be multiples of \( 2\pi \).
When the diver completes 2.5 revolutions, we can find the total angular displacement by multiplying the number of revolutions by the angular displacement for one revolution:
\[ a = 2.5 \times 2\pi \]\[ a = 5\pi \text{ radians} \]
This figure is essential for calculating the average angular velocity; it represents the total 'distance' the diver has rotated through.
Rotational Kinematics
Rotational kinematics involves the description of the motion of rotating objects without necessarily addressing forces and mass. It is akin to linear kinematics but for rotation. The primary quantities involved are rotational versions of displacement, velocity, and acceleration. Average angular velocity, which we wish to calculate for the diver, is an analog to linear velocity but in the rotational sense.
Its formula is:
\[ \omega = \frac{a}{t} \]
where \( \omega \) is the average angular velocity, \( a \) is the Angular Displacement, and \( t \) is the time taken to rotate through angle \( a \). To calculate the average angular velocity of our tumbling diver, we use the angular displacement from the 'Angular Displacement' section and the time of fall calculated using the 'Equations of Motion.' By placing these values into the above formula, we obtain the diver's average angular velocity, which tells us the average rate at which he is rotating as he falls toward the water.

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Most popular questions from this chapter

A speedometer on the front wheel of a bicycle gives a reading that is directly proportional to the angular speed of the wheel. Suppose that such a speedometer is calibrated for a wheel of diameter \(72 \mathrm{~cm}\) but is mistakenly used on a wheel of diameter \(62 \mathrm{~cm} .\) Would the linear speed reading be wrong? If so, in what sense and by what fraction of the true speed?

A point on the rim of a \(0.75\) -m-diameter grinding wheel changes speed uniformly from \(12 \mathrm{~m} / \mathrm{s}\) to \(25 \mathrm{~m} / \mathrm{s}\) in \(6.2 \mathrm{~s}\). What is the angular acceleration of the grinding wheel during this interval?

The angular speed of an automobile engine is increased uniformly from 1170 rev/min to 2880 rev/min in \(12.6 \mathrm{~s}\). (a) Find the angular acceleration in rev/min \(^{2} .(b)\) How many revolutions does the engine make during this time?

The blades of a windmill start from rest and rotate with an angular acceleration of \(0.236 \mathrm{rad} / \mathrm{s}^{2} .\) How much time elapses before a point on a blade experiences the same value for the magnitudes of the centripetal acceleration and tangential acceleration?

A certain wheel turns through 90 rev in \(15 \mathrm{~s}\), its angular speed at the end of the period being \(10 \mathrm{rev} / \mathrm{s} .(a)\) What was the angular speed of the wheel at the beginning of the 15 -s interval, assuming constant angular acceleration? \((b)\) How much time had elapsed between the time the wheel was at rest and the beginning of the 15 -s interval?

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