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The speeds of a group of ten molecules are \(2.0,3.0,4.0, \ldots\), \(11 \mathrm{~km} / \mathrm{s}\). ( \(a\) ) Find the average speed of the group. (b) Calculate the root-mean-square speed of the group.

Short Answer

Expert verified
(a) The average speed of the group is 6.0 km/s (b) The root-mean-square speed of the group is approximately 7.10 km/s.

Step by step solution

01

Calculate Average Speed

The average speed can be calculated by adding up all the molecule speeds, and then dividing by the count of molecules. Here are the speeds: \(2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0, 11.0\) km/s, totaling ten molecules. Summing these up equals 60 km/s. Thus, the average speed equals \(\frac{60 \text{ km/s}}{10} = 6.0 \text{ km/s}\).
02

Calculate Square of Each Speed

In order to calculate the root-mean-square speed, we first need to find the square of each molecule's speed. The squared speeds are: \(4.0, 9.0, 16.0, 25.0, 36.0, 49.0, 64.0, 81.0, 100.0, 121.0\) (km/s)\(^2\).
03

Calculate Root-Mean-Square Speed

The root-mean-square speed is found by taking the square root of the average of these squared speeds. Add up the squared speeds to get 505 (km/s)\(^2\), and divide by the number of molecules (10) to find the average, which equals 50.5 (km/s)\(^2\). Taking the square root of this gives approximately 7.10 km/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Speed
To understand average speed in the context of molecular speeds, think of it as the typical speed at which a molecule travels within a group. Calculating the average speed is straightforward. Follow these steps:
  • Sum up all of the individual speeds.
  • Divide the total by the number of molecules.
In the exercise, we have ten molecules traveling at different speeds ranging from 2.0 km/s to 11.0 km/s. The total comes to 60.0 km/s when all these speeds are added together. Dividing by ten molecules, the result is 6.0 km/s as the average speed. This provides a simple snapshot of how fast the molecules are moving overall.
Root-Mean-Square Speed
Root-mean-square (RMS) speed offers a different perspective. It reflects the average speed of molecules on a more mathematically intricate level. The key here is the emphasis on the 'square'. It's particularly useful in assessing kinetic energy in gases. Here's how you calculate it:
  • Square each molecule's speed individually.
  • Take the average of these squared speeds.
  • Finally, take the square root of this average.
For the given speeds, we calculate each squared speed and sum them up to 505 (km/s) extsuperscript{2}. Averaging over ten molecules gives 50.5 (km/s) extsuperscript{2}. The square root of this value yields approximately 7.10 km/s as the RMS speed.
Kinetic Theory of Gases
The kinetic theory of gases provides a framework for understanding gaseous behavior. It ties together molecular movements and gas properties like pressure and temperature. The theory is based on several assumptions:
  • Gases consist of numerous small particles (molecules).
  • These molecules move in random directions with various speeds.
  • Collisions between molecules or with container walls are perfectly elastic.
These assumptions lead to the relationship between temperatures and molecular speeds. Higher temperatures correspond to higher average molecular speeds. This fundamental notion links to both average and RMS speeds, showing how molecular motion represents macroscopic gas properties.
Statistical Mechanics
Statistical mechanics takes the concepts of classical mechanics into the micro-world of particles, such as gas molecules. By applying statistics to vast numbers of particles, it bridges the gap between macroscopic and microscopic phenomena. Two key aspects:
  • It considers probabilities of different molecular states and speeds.
  • Derives macroscopic properties from microscopic behaviors.
In the context of our exercise, statistical mechanics helps explain why average and RMS speeds differ. Each reflects different statistical measures of the molecular motion within a gas. Insights from statistical mechanics allow us to predict properties of complex systems, reinforcing reliable models of real-world gases.

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Most popular questions from this chapter

(a) Find the number of molecules in \(1.00 \mathrm{~m}^{3}\) of air at \(20.0^{\circ} \mathrm{C}\) and at a pressure of \(1.00 \mathrm{~atm} .(b)\) What is the mass of this volume of air? Assume that \(75 \%\) of the molecules are nitrogen \(\left(\mathrm{N}_{2}\right)\) and \(25 \%\) are oxygen \(\left(\mathrm{O}_{2}\right)\).

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You are given the following group of particles \(\left(N_{n}\right.\) represents the number of particles that have a speed \(v_{n}\) ): $$\begin{array}{lc}N_{n} & v_{n}(\mathrm{~km} / \mathrm{s}) \\\\\hline 2 & 1.0 \\\4 & 2.0 \\\6 & 3.0 \\\8 & 4.0 \\\2 & 5.0\end{array}$$ (a) Compute the average speed \(v_{\mathrm{av}} .(b)\) Compute the rootmean- square speed \(v_{\text {rms. }}\) (c) Among the five speeds shown, which is the most probable speed \(v_{\mathrm{p}}\) for the entire group?

A steel tank contains \(315 \mathrm{~g}\) of ammonia gas \(\left(\mathrm{NH}_{3}\right)\) at an absolute pressure of \(1.35 \times 10^{6} \mathrm{~Pa}\) and temperature \(77.0^{\circ} \mathrm{C} .(a)\) What is the volume of the tank? \((b)\) The tank is checked later when the temperature has dropped to \(22.0^{\circ} \mathrm{C}\) and the absolute pressure has fallen to \(8.68 \times 10^{5} \mathrm{~Pa}\). How many grams of gas leaked out of the tank?

At what frequency would the wavelength of sound be on the order of the mean free path in nitrogen at \(1.02\) atm pressure and \(18.0^{\circ} \mathrm{C} ?\) Take the diameter of the nitrogen molecule to be \(315 \mathrm{pm}\)

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