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Absolute zero is \(-273.15^{\circ} \mathrm{C}\). Find absolute zero on the Fahrenheit scale.

Short Answer

Expert verified
Absolute zero in Fahrenheit scale is \(-459.67^{\circ} \mathrm{F}\).

Step by step solution

01

Identify the given temperature in Celsius

The temperature given is absolute zero, which is \(-273.15^{\circ} \mathrm{C}\). This is the value we will need to convert into Fahrenheit.
02

Apply the conversion formula

The formula to convert from Celsius to Fahrenheit is \( F = C \times \frac{9}{5} + 32 \). Substituting in the given Celsius temperature, we get \( F = -273.15 \times \frac{9}{5} + 32 \).
03

Calculate the temperature in Fahrenheit

Perform the multiplication and addition to find the temperature in Fahrenheit. Plugging it into a calculator, we get \( F = -459.67 ^{\circ} \mathrm{F} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Temperature Conversion
Understanding how to convert temperature from one unit to another is essential in various fields like meteorology, science, and even cooking. Temperature conversion between Celsius and Fahrenheit can be perplexing due to the different starting points and scaling factors the two systems use. The basic formula to convert from Celsius to Fahrenheit is
\[\begin{equation} F = C \times \frac{9}{5} + 32 \end{equation}\].
Here, F represents the temperature in Fahrenheit, C is the temperature in Celsius, and \(\frac{9}{5}\) with an addition of 32 accounts for the scaling and offset differences between the two scales. It's important for students to remember this formula and understand that the number 32 is added because the Fahrenheit scale starts at a higher temperature compared to Celsius for the point defined as freezing (32°F is equal to 0°C).
Celsius to Fahrenheit
In the conversion from Celsius to Fahrenheit, every degree Celsius is equivalent to 1.8 degrees Fahrenheit. To successfully convert temperatures, you should first multiply the Celsius temperature by 1.8 (or \(\frac{9}{5}\)) then add 32 to the result. This operation reflects the relative size of Celsius and Fahrenheit degrees and the temperature difference between the two scales' zero points.
For example, when converting absolute zero from Celsius to Fahrenheit, you multiply -273.15 by 1.8 and then add 32, resulting in the Fahrenheit scale equivalent of -459.67°F. This conversion is particularly important when dealing with scientific data, as precision is crucial and even small variations in temperature can lead to significant variations in experimental outcomes.
Thermodynamic Temperature Scale
The thermodynamic temperature scale, often referred to as the absolute temperature scale, is key to understanding the concept of absolute zero. This scale is based on the laws of thermodynamics and is independent of the properties of any specific material. The Kelvin scale is an example of a thermodynamic temperature scale and it starts at absolute zero, the theoretical point where particles have minimum thermal motion.
Absolute zero is 0 K, which is equivalent to -273.15°C. This is the basis for a pivotal temperature reference point in scientific work. It's significant that unlike Celsius or Fahrenheit, Kelvin does not use degrees; a temperature difference of one Kelvin is the same magnitude as one degree Celsius. This universality makes the Kelvin scale particularly useful in the scientific community, providing a clear standard for temperature measurements.

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Most popular questions from this chapter

A resistance thermometer is a thermometer in which the electrical resistance changes with temperature. We are free to define temperatures measured by such a thermometer in kelvins (K) to be directly proportional to the resistance \(R\), measured in ohms \((\Omega) .\) A certain resistance thermometer is found to have a resistance \(R\) of \(90.35 \Omega\) when its bulb is placed in water at the triple-point temperature \((273.16 \mathrm{~K}) .\) What temperature is indicated by the thermometer if the bulb is placed in an environment such that its resistance is \(96.28 \Omega ?\)

An air bubble of \(19.4 \mathrm{~cm}^{3}\) volume is at the bottom of a lake \(41.5 \mathrm{~m}\) deep where the temperature is \(3.80^{\circ} \mathrm{C}\). The bubble rises to the surface, which is at a temperature of \(22.6^{\circ} \mathrm{C}\). Take the temperature of the bubble to be the same as that of the surrounding water and find its volume just before it reaches the surface.

An aluminum cup of \(110 \mathrm{~cm}^{3}\) capacity is filled with glycerin at \(22^{\circ} \mathrm{C}\). How much glycerin, if any, will spill out of the cup if the temperature of the cup and glycerin is raised to \(28^{\circ} \mathrm{C}\) ? (The coefficient of volume expansion of glycerin is \(5.1 \times\) \(\left.10^{-4} / \mathrm{C}^{\circ} .\right)\)

( \(a\) ) Prove that the change in period \(P\) of a physical pendulum with temperature is given by \(\Delta P=\frac{1}{2} \alpha P \Delta T .(b)\) A clock pendulum made of invar has a period of \(0.500 \mathrm{~s}\) and is accurate at \(20^{\circ} \mathrm{C}\). If the clock is used in a climate where the temperature averages \(30^{\circ} \mathrm{C}\), what approximate correction to the time given by the clock is necessary at the end of 30 days?

(a) Using the ideal gas law and the definition of the coefficient of volume expansion (Eq. \(21-12\) ), show that \(\beta=1 / T\) for an ideal gas at constant pressure. \((b)\) In what units must \(T\) be expressed? If \(T\) is expressed in those units, can you express \(\beta\) in units of \(\left(\mathrm{C}^{\circ}\right)^{-1} ?(c)\) Estimate the value of \(\beta\) for an ideal gas at room temperature.

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