Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find the speed parameter \(\beta\) and the Lorentz factor \(\gamma\) for a particle whose kinetic energy is \(10 \mathrm{MeV}\) if the particle is \((a)\) an electron, \((b)\) a proton, and \((c)\) an alpha particle.

Short Answer

Expert verified
The Lorentz factor and speed parameter for the three particles are calculated individually by using their respective rest masses. They are calculated using the formulas for kinetic energy and speed parameter in special relativity.

Step by step solution

01

Determine the Rest Mass

Determine the rest mass for each particle. The rest mass of an electron (me) is approximately \(0.511 \mathrm{MeV}/c^2\), of a proton (mp) is about \(938.27 \mathrm{MeV}/c^2\), and of an alpha particle (mĪ±) is about \(3727.4 \mathrm{MeV}/c^2\).
02

Calculate the Lorentz Factor

Calculate the Lorentz factor \(\gamma\) for each particle using the kinetic energy formula. Inversely, the formula \(\gamma = \frac{KE}{mc^2} + 1\) can be used. KE is given as \(10 \mathrm{MeV}\). Plug the values into the formula to get the value of \(\gamma\).
03

Calculate the Speed Parameter

Calculate the speed parameter \(\beta\) using the formula \(\beta^2 = 1 - \frac{1}{\gamma^2}\). After calculating the Lorentz factor in the previous step, substitute \(\gamma\) in the formula to get \(\beta\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy in relativistic mechanics is slightly different from classical mechanics. It takes into account the effects of relativity, especially when particles travel at speeds close to the speed of light. In this context, the standard formula for kinetic energy is modified. The relativistic kinetic energy (\( KE \)) of a particle is given by the equation:

\[KE = (\gamma - 1) m c^2\]
Here, \( \gamma \) is the Lorentz factor, \( m \) is the rest mass, and \( c \) is the speed of light. This formula accounts for how energy increases significantly as a particle's speed approaches light speed.

The inclusion of the Lorentz factor in kinetic energy formulas reflects how energy isn't linear as speed increases. Instead, it's influenced by relativistic effects, showing why the study of particles moving close to light speed requires a more complex approach than classical mechanics.
Lorentz Factor
The Lorentz factor is crucial when dealing with high-speed particles. It is defined as:

\[\gamma = \frac{1}{\sqrt{1-\beta^2}}\]
Here, \( \beta = \frac{v}{c} \) is the speed parameter. The Lorentz factor describes how much time dilation, length contraction, and relativistic mass increase occur as an object's speed approaches the speed of light.
  • When \( \beta = 0 \) (stationary object), \( \gamma = 1 \). No relativistic effects are observed.
  • As \( \beta \) approaches 1, \( \gamma \) increases significantly, enhancing relativistic effects.
The Lorentz factor is essential for calculating relativistic kinetic energy and helps in understanding how particles behave at extremely high speeds. It provides a way to measure just how much the laws of physics adjust compared to everyday experiences.
Rest Mass
Rest mass, often denoted as \( m_0 \), is the mass of a particle when it is at rest. It's an intrinsic property of the particle and remains constant regardless of its speed. In relativistic contexts, rest mass is crucial because it forms the basis for calculating other properties.

Rest mass is used in the relativistic energy and kinetic energy formulas. For instance:

\[E = \gamma m_0 c^2\]
Here, \( E \) represents the total energy of the particle. In the original exercise, the rest masses allow for the calculation of the Lorentz factor and kinetic energy of each particle type (electron, proton, alpha particle). Each has a different rest mass and thus behaves differently under the same kinetic energy conditions.
Speed Parameter
The speed parameter \( \beta \) is defined as the ratio of a particle's velocity to the speed of light:

\[\beta = \frac{v}{c}\]
\( \beta \) is dimensionless and typically ranges from 0 to nearly 1 for many particles studied in relativistic mechanics. A \( \beta \) value of 1 implies that the particle is moving at the speed of light, which is impossible for particles with mass.
  • As \( \beta \) increases, relativistic effects become more pronounced.
  • In calculations, knowing \( \beta \) aids in determining the Lorentz factor, \( \gamma \), which further helps compute kinetic energy.
Understanding \( \beta \) helps clarify how particles behave under high-speed conditions, making it an essential part of analyzing and predicting particle behavior in relativistic mechanics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An alpha particle with kinetic energy \(7.70 \mathrm{MeV}\) strikes a \({ }^{14} \mathrm{~N}\) nucleus at rest. An \({ }^{17} \mathrm{O}\) nucleus and a proton are produced, the proton emitted at \(90^{\circ}\) to the direction of the incident alpha particle and carrying kinetic energy \(4.44 \mathrm{MeV}\). The rest energies of the various particles are: alpha particle, \(3730.4 \mathrm{MeV}\); \({ }^{14} \mathrm{~N}, 13,051 \mathrm{MeV} ;\) proton, \(939.29 \mathrm{MeV} ;{ }^{17} \mathrm{O}, 15,843 \mathrm{MeV}\) (a) Find the kinetic energy of the \({ }^{17} \mathrm{O}\) nucleus. (b) At what angle with respect to the direction of the incident alpha particle does the \({ }^{17} \mathrm{O}\) nucleus move?

Consider the following, all moving in free space: a \(2.0\) -eV photon, a \(0.40-\mathrm{MeV}\) electron, and a \(10-\mathrm{MeV}\) proton. \((a)\) Which is moving the fastest? (b) The slowest? ( \(c\) ) Which has the greatest momentum? \((d)\) The least? (Note: A photon is a light particle of zero mass.)

To circle the Earth in low orbit a satellite must have a speed of about \(7.91 \mathrm{~km} / \mathrm{s}\). Suppose that two such satellites orbit the Earth in opposite directions. (a) What is their relative speed as they pass? Evaluate using the classical Galilean velocity transformation equation. (b) What fractional error was made because the (correct) relativistic transformation equation was not used?

A \(100-\mathrm{MeV}\) electron, for which \(v=0.999987 c\), moves along the axis of an evacuated tube that has a length of \(2.86 \mathrm{~m}\) as measured by a laboratory observer \(S\) with respect to whom the tube is at rest. An observer \(S^{\prime}\) moving with the electron, however, would see this tube moving past with speed \(v\). What length would this observer measure for the tube?

What must be the value of the speed parameter \(\beta\) if the Lorentz factor \(\gamma\) is to be \((a) 1.01 ?(b) 10.0 ?(c) 100 ?(d)\) \(1000 ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free