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The head of a rattlesnake can accelerate \(50 \mathrm{~m} / \mathrm{s}^{2}\) in striking a victim. If a car could do as well, how long would it take for it to reach a speed of \(100 \mathrm{~km} / \mathrm{h}\) from rest?

Short Answer

Expert verified
It would take the car 0.56 seconds to reach a speed of 100 km/h from rest if it could accelerate at 50 m/s².

Step by step solution

01

Convert Velocity to Compatible Units

First convert the final velocity from kilometers per hour to meters per second. 100 km/h is equal to approximately 27.78 m/s.
02

Apply the Acceleration Formula

Using the formula for acceleration (v = u + at), where v = 27.78 m/s, u = 0 m/s and a = 50 m/s², solve for t. Substituting the values into the formula, we get 27.78 = 0 + 50t
03

Calculate Time

Rearranging the acceleration formula, we get the time t = 27.78 / 50 = 0.56 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of classical mechanics that describes the motion of points, bodies, and systems of bodies without considering the forces that cause them to move. At the core of kinematics is the study of an object's velocity and acceleration. Velocity is the speed of an object in a particular direction, while acceleration is the rate at which an object's velocity changes over time.

When studying kinematics, we often look at various graphs and equations to model motion. For instance, velocity-time graphs can help us understand how an object's speed changes and what that implies about the object's acceleration. An important aspect of kinematics is the distinction between uniform motion (at constant velocity) and uniformly accelerated motion (at constant acceleration). In your rattlesnake example, the snake's head is described as having a constant acceleration, which is a classic case of uniformly accelerated motion.

By using kinematic equations, we can predict future states of motion, such as where an object will be after a certain period and how fast it will be going.
Unit Conversion
In physics, unit conversion is a critical step that students must master to solve problems accurately. Different systems of measurement can be used depending on the context, such as the International System of Units (SI) for scientific measurements. The SI unit for measuring velocity or speed is meters per second (m/s), while for everyday contexts, kilometers per hour (km/h) is commonly used.

To convert units, you typically use a conversion factor that represents the ratio of one unit to another. For example, to convert from km/h to m/s, you can use the conversion factor where 1 km/h equals approximately 0.2778 m/s. This is what was done in Step 1 of the solution, where the car's speed was converted into meters per second before using the acceleration formula.

Understanding and applying unit conversion is essential because it ensures that all the units in a formula are consistent, preventing errors in calculation. A failure to convert units correctly can lead to incorrect results and a misinterpretation of the motion being analyzed.
Motion Equations
Motion equations, also known as the equations of motion, are mathematical relationships that describe an object's kinematics. These equations enable us to predict the final position, velocity, and time elapsed for an object under uniform acceleration. To solve the rattlesnake head acceleration problem, the equation used was one of the basic motion equations given by: \( v = u + at \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.

In problems involving constant acceleration, the final velocity can be found if you know the initial velocity, acceleration, and time. Conversely, if you know the final and initial velocities, and the acceleration, you can find the time as shown in Step 3. There are several motion equations, and they are typically taught as part of introductory physics courses because they apply to a wide range of everyday phenomena.

These equations underpin much of classical mechanics and are vital tools in engineering, physics, and various applied sciences. They are simple yet powerful, allowing prediction of an object’s future motion from the current state of motion and known forces.

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Most popular questions from this chapter

A car travels up a hill at the constant speed of \(40 \mathrm{~km} / \mathrm{h}\) and returns down the hill at the speed of \(60 \mathrm{~km} / \mathrm{h} .\) Calculate the average speed for the round trip.

An automobile traveling \(35 \mathrm{mi} / \mathrm{h}(=56 \mathrm{~km} / \mathrm{h})\) is \(110 \mathrm{ft}(=34\) \(\mathrm{m}\) ) from a barrier when the driver slams on the brakes. Four seconds later the car hits the barrier. ( \(a\) ) What was the automobile's constant deceleration before impact? (b) How fast was the car traveling at impact?

Maurice Greene once ran the \(100-\mathrm{m}\) dash in \(9.81 \mathrm{~s}\) (the wind was at his back), and Khalid Khannouchi ran the marathon (26 mi, 385 yd) in 2:05:42. (a) What are their average speeds? (b) If Maurice Greene could maintain his sprint speed during a marathon, how long would it take him to finish?

The single cable supporting an unoccupied construction elevator breaks when the elevator is at rest at the top of a \(120-\mathrm{m}\) high building. ( \(a\) ) With what speed does the elevator strike the ground? \((b)\) For how long was it falling? \((c)\) What was its speed when it passed the halfway point on the way down? ( \(d\) ) For how long was it falling when it passed the halfway point?

(a) What is the sum in unit-vector notation of the two vectors \(\overrightarrow{\mathbf{a}}=5 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}\) and \(\overrightarrow{\mathbf{b}}=-3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}} ?(b)\) What are the magni- tude and the direction of \(\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}\) ?

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