Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How far does your car, moving at \(70 \mathrm{mi} / \mathrm{h}(=112 \mathrm{~km} / \mathrm{h})\) travel forward during the \(1 \mathrm{~s}\) of time that you take to look at an accident on the side of the road?

Short Answer

Expert verified
During the 1 second that a driver takes to look at an accident on the side of the road, the car (moving at 70 mph) will travel approximately \(0.019444 \) miles forward.

Step by step solution

01

Understanding the problem

The important piece of information in this exercise is that the car is moving at a speed of 70 mph (or 112 km/h). We want to find out how far the car travels in 1 second. The unit of speed given (miles or kilometers per hour) is not compatible with the time given (in seconds), so we'll need to do a unit conversion.
02

Converting Units

Let's convert the speed from mph to miles per second. We know that 1 hour is equal to 3600 seconds. Therefore, we divide the speed by 3600 to get the speed in miles per second, \(70 \, mph \,/\, 3600 = 0.019444 \, miles/s\). Now the units of speed and time are compatible.
03

Calculating Distance

We know that distance = speed x time. So we multiply the speed in miles per second (0.019444 miles/s) by the time (1 second) to find out how far the car travels in that time. \(Distance = 0.019444 \, miles/s \times 1 \, s = 0.019444 \, miles\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed Calculation
Speed calculation is the key to understanding how fast something is moving. It determines the rate at which an object covers distance over time. In our example, the car is moving at a speed of 70 miles per hour. Of course, understanding speed in miles per hour can be common in everyday scenarios, but it is crucial to remember this is only applicable when the time is factored in hours.

To calculate speed properly, you typically need two components:
  • Distance traveled - in this case, miles
  • Time taken - here it's shown in hours
These components together give you the average speed using the formula:\[\text{Speed} = \frac{\text{Distance}}{\text{Time}}\]In scenarios requiring different units, like our example where time is in seconds, you need a unit conversion, which ensures that calculations remain accurate and meaningful.
Distance Calculation
The purpose of distance calculation is to find out how far an object travels. With the speed known, and the time taken to cover the distance given, you can calculate the distance. This comes down to a straightforward equation of using the speed and time to find out the travel length.

The famous formula for calculating distance is:\[\text{Distance} = \text{Speed} \times \text{Time}\]For the exercise, we've already converted the speed from miles per hour to miles per second, resulting in \(0.019444\) miles per second.

By multiplying this speed by the 1 second of time provided, the distance calculation becomes simple. So, in this problem, the car travels a short distance of \(0.019444\) miles.
Time Conversion
Time conversion is crucial when dealing with speed and distance calculations, as it ensures all units align correctly. In our situation, the initial unit of speed is in hours, whereas time given is in seconds. Thus, conversion clears any discrepancy.

A straightforward conversion is needed:- Convert hours to seconds to match the time unit given in seconds.We know there are 3600 seconds in an hour, so it's necessary to adjust the speed from miles per hour to miles per second by dividing by 3600:
\[70 \, mp/h \div 3600 = 0.019444 \, miles/second\]Now, with speed and time both in compatible units, calculations are much simpler and more precise whether they involve distance traveled or determining speed over different time intervals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A ship sets out to sail to a point \(124 \mathrm{~km}\) due north. An unexpected storm blows the ship to a point \(72.6 \mathrm{~km}\) to the north and \(31.4 \mathrm{~km}\) to the east of its starting point. How far, and in what direction, must it now sail to reach its original destination?

Maurice Greene once ran the \(100-\mathrm{m}\) dash in \(9.81 \mathrm{~s}\) (the wind was at his back), and Khalid Khannouchi ran the marathon (26 mi, 385 yd) in 2:05:42. (a) What are their average speeds? (b) If Maurice Greene could maintain his sprint speed during a marathon, how long would it take him to finish?

A dog sees a flowerpot sail up and then back down past a window \(1.1 \mathrm{~m}\) high. If the total time the pot is in sight is \(0.54 \mathrm{~s}\), find the height above the top of the window to which the pot rises.

The velocity of a particle moving in the \(x y\) plane is given by \(\overrightarrow{\mathbf{v}}=\left[\left(6.0 \mathrm{~m} / \mathrm{s}^{2}\right) t-\left(4.0 \mathrm{~m} / \mathrm{s}^{3}\right) t^{2}\right] \hat{\mathbf{i}}+(8.0 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}\). Assume \(t>0 .(a)\) What is the acceleration when \(t=3 \mathrm{~s} ?(b)\) When (if ever) is the acceleration zero? \((c)\) When (if ever) is the velocity zero? \((d)\) When (if ever) does the speed equal \(10 \mathrm{~m} / \mathrm{s}\) ?

(a) What are the components of a vector \(\overrightarrow{\mathbf{a}}\) in the \(x y\) plane if its direction is \(252^{\circ}\) counterclockwise from the positive \(x\) axis and its magnitude is \(7.34\) units? \((b)\) The \(x\) component of a certain vector is \(-25\) units and the \(y\) component is \(+43\) units. What are the magnitude of the vector and the angle between its direction and the positive \(x\) axis?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free