Chapter 16: Problem 29
Liquid mercury (viscosity \(=1.55 \times 10^{-3} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\) ) flows through a horizontal pipe of internal radius \(1.88 \mathrm{~cm}\) and length \(1.26 \mathrm{~m}\). The volume flux is \(5.35 \times 10^{-2} \mathrm{~L} / \mathrm{min}\). \((a)\) Show that the flow is laminar. (b) Calculate the difference in pressure between the two ends of the pipe.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.