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Two vectors, \(\overrightarrow{\mathbf{r}}\) and \(\overrightarrow{\mathbf{s}}\), lie in the \(x y\) plane. Their magnitudes are \(4.5\) and \(7.3\) units, respectively, whereas their directions are \(320^{\circ}\) and \(85^{\circ}\) measured counterclockwise from the positive \(x\) axis. What is the value of \(\overrightarrow{\mathbf{r}} \cdot \overrightarrow{\mathbf{s}}\) ?

Short Answer

Expert verified
The value of \(\overrightarrow{r} \cdot \overrightarrow{s}\) is approximately -21.014 units.

Step by step solution

01

Calculate the angle between the vectors

The direction of \(\overrightarrow{r}\) is \(320^\circ\) and the direction of \(\overrightarrow{s}\) is \(85^\circ\). Since these angles are measured counterclockwise from the positive x-axis, the angle between the vectors (\(\theta\)) can be calculated as the absolute difference between the two angles. So, \(\theta = |320^\circ - 85^\circ| = 235^\circ\).
02

Convert the angle to radians

The cosine function in most calculators and programming languages uses radians instead of degrees, so convert \(\theta\) into radians: \(\theta_{\text{rad}} = 235^\circ * \(\pi / 180\) = 4.10152 \text{ rad}\).
03

Compute the dot product

The dot product of vectors \(\overrightarrow{r}\) and \(\overrightarrow{s}\) is defined as \(|\overrightarrow{r}| * |\overrightarrow{s}| * cos(\theta)\). Substituting the given magnitudes of the vectors and the calculated angle: \(\overrightarrow{r} \cdot \overrightarrow{s} = 4.5 * 7.3 * cos(4.10152) = -21.014 units\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product Calculation
The dot product, also known as the scalar product, is a fundamental operation in vector algebra that measures the product of two vectors' magnitudes and the cosine of the angle between them. The formula is given as:
\[ \bz {A} \cdot \bz {B} = |\bz {A}| \times |\bz {B}| \times \cos(\theta) \]
Pictorially, if vector \(\bz {A}\) projects onto vector \(\bz {B}\), the dot product gives us the magnitude of this projection times the magnitude of \(\bz {B}\). In the context of our exercise, we're looking to calculate the dot product of vectors \(\bz r\) and \(\bz s\) with magnitudes of 4.5 and 7.3 units respectively, and an angle \(\theta\) of 235 degrees between them. After converting this angle to radians (which is necessary for most mathematical computations), we can apply the formula to find the dot product.
Polar Coordinates
Polar coordinates are a two-dimensional coordinate system in which each point on a plane is determined by an angle and a distance from a reference point known as the pole, similar to the way an angle and magnitude determine the position of a vector in the plane.
In polar coordinates, the angle is often represented by \(\theta\) and usually measured in degrees or radians from the positive x-axis, counterclockwise. The distance from the pole is analogous to the vector's magnitude. Our vectors \(\bz r\) and \(\bz s\) in the exercise have their directions given in degrees as measured from the positive x-axis, which corresponds to their polar angle, and their magnitudes correspond to the radial distance from the origin. Understanding polar coordinates is key to visualizing and solving problems related to vectors in a plane.
Converting Degrees to Radians
Degrees and radians are two units for measuring angles. There are 360 degrees or \(2\pi\) radians in a complete circle. To convert from degrees to radians, we use the conversion factor \(\pi/180\).
In the exercise, the angle between two vectors is 235 degrees, which we need to convert to radians to use in mathematical functions such as cosine.
The conversion is done as follows:
\[\theta_{\text{rad}} = \theta_{\text{deg}} \times \left(\frac{\pi}{180}\right)\]
Applying this to our angle:
\[235^\circ \times \left(\frac{\pi}{180}\right) = 4.10152 \text{ rad}\]
It's crucial for students to become comfortable with this conversion because radians are the standard unit of angular measure in most scientific and technical calculations.

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Most popular questions from this chapter

The last stage of a rocket is traveling at a speed of \(7600 \mathrm{~m} / \mathrm{s}\). This last stage is made up of two parts that are clamped together - namely, a rocket case with a mass of \(290.0 \mathrm{~kg}\) and a payload capsule with a mass of \(150.0 \mathrm{~kg}\). When the clamp is released, a compressed spring causes the two parts to separate with a relative speed of \(910.0 \mathrm{~m} / \mathrm{s}\). ( \(a\) ) What are the speeds of the two parts after they have separated? Assume that all velocities are along the same line. \((b)\) Find the total kinetic energy of the two parts before and after they separate and account for the difference, if any.

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\((a)\) Calculate \(\overrightarrow{\mathbf{r}}=\overrightarrow{\mathbf{a}}-\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}}\), where \(\overrightarrow{\mathbf{a}}=5 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}-6 \hat{\mathbf{k}}\), \(\overrightarrow{\mathbf{b}}=-2 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\), and \(\overrightarrow{\mathbf{c}}=4 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}} .\) (b) Calculate the angle between \(\overrightarrow{\mathbf{r}}\) and the \(+z\) axis. ( \(c\) ) Find the angle between \(\overrightarrow{\mathbf{a}}\) and \(\overrightarrow{\mathbf{b}}\).

The oxygen molecule has a total mass of \(5.30 \times 10^{-26} \mathrm{~kg}\) and a rotational inertia of \(1.94 \times 10^{-46} \mathrm{~kg} \cdot \mathrm{m}^{2}\) about an axis through the center perpendicular to the line joining the atoms. Suppose that such a molecule in a gas has a mean speed of \(500 \mathrm{~m} / \mathrm{s}\) and that its rotational kinetic energy is two- thirds of its translational kinetic energy. Find its average angular velocity.

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