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A unit of area, often used in expressing areas of land, is the hectare, defined as \(10^{4} \mathrm{~m}^{2}\). An open-pit coal mine consumes 77 hectares of land, down to a depth of \(26 \mathrm{~m}\), each year. What volume of earth, in cubic kilometers, is removed in this time?

Short Answer

Expert verified
The volume of earth removed each year is 0.02002 cubic kilometers

Step by step solution

01

Convert area from hectares to square meters

Given that 1 hectare equals \(10^{4} m^{2}\), the total area is \(77 hectares * 10^{4} m^{2}/hectare = 770000 m^{2}\)
02

Calculate volume in cubic meters

The volume in cubic meters can be calculated by multiplying the area by the depth. Volume = area * depth = \(770000 m^{2} * 26 m = 20020000 m^{3}\).
03

Convert volume from cubic meters to cubic kilometers

Since 1 cubic kilometer equals \(10^{9} m^{3}\), we divided the volume in cubic meters by \(10^{9} m^{3}/km^{3}\) to get the volume in cubic kilometers. Volume = \(20020000 m^{3}/10^{9} m^{3}/km^{3} = 0.02002 km^{3}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Area Conversion
When you hear about converting area measurements, it's usually about changing units from one system to another, like hectares to square meters. This is a crucial step when you need detailed measurements for calculations.
For instance, 1 hectare is a popular unit of area that's used quite often in agriculture and land measurement. It's equivalent to 10,000 square meters. When you're told that your plot of land is "x" hectares, you are essentially saying it's "x times 10,000" in square meters.
This conversion helps simplify more complex operations, like calculating volume, which depends on the area of the surface you're working with. So, if you have 77 hectares, as in our exercise, you'll multiply by 10,000 to find out what that is in square meters, which is particularly useful when you're calculating the volume of earth displaced during mining or construction.
Unit Conversion
Unit conversion is like translating a sentence into a different language; only the language is numbers. It allows us to comprehend information in units we are familiar with or that are more practical for our purposes, such as converting volume from cubic meters to cubic kilometers.
This task can seem complicated, but it often involves straightforward multiplication or division. For our exercise, converting the volume from cubic meters to cubic kilometers involves dividing by 1,000,000,000 since 1 cubic kilometer contains 1 billion cubic meters. This helps you understand the magnitude of the number in a more comprehensible scale.
Being adept at unit conversion is especially critical in large-scale operations, like mining, where dealing with a multitude of units could lead to errors if not handled carefully. Practicing with smaller scale conversions builds the skill sets necessary for interpreting and manipulating data accurately.
Volume of Earth
Calculating the volume of earth removed, as we explored in the given exercise, involves understanding area and depth. Volume calculation becomes an essential task here to gauge the scale of operations like mining or excavation.
We calculate the volume by multiplying the converted area (in square meters) by depth (in meters). This provides the volume in cubic meters. Since operations over large areas, like the open-pit mine example, result in enormous volumes, these are typically represented in cubic kilometers for convenience. For instance, 20,020,000 cubic meters, once converted, equals about 0.02002 cubic kilometers.
Understanding these large numbers is crucial, as they can influence decisions about logistics, environmental impact assessments, and resource management strategies in industries that manipulate large volumes of earth.

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Most popular questions from this chapter

(a) A unit of time sometimes used in microscopic physics is the shake. One shake equals \(10^{-8} \mathrm{~s}\). Are there more shakes in a second than there are seconds in a year? (b) Humans have existed for about \(10^{6}\) years, whereas the universe is about \(10^{10}\) years old. If the age of the universe is taken to be 1 day, for how many seconds have humans existed?

The effective radius of a proton is about \(1 \times 10^{-15} \mathrm{~m} ;\) the radius of the observable universe (given by the distance to the farthest observable quasar) is \(2 \times 10^{26} \mathrm{~m}\) (see Table \(1-4\) ). Identify a physically meaningful distance that is approximately halfway between these two extremes on a logarithmic scale.

Astronomical distances are so large compared to terrestrial ones that much larger units of length are used for easy comprehension of the relative distances of astronomical objects. An astronomical unit \((\mathrm{AU})\) is equal to the average distance from Earth to the Sun, \(1.50 \times 10^{8} \mathrm{~km}\). A parsec (pc) is the distance at which 1 AU would subtend an angle of 1 second of arc. A light-year (ly) is the distance that light, traveling through a vacuum with a speed of \(3.00 \times 10^{5} \mathrm{~km} / \mathrm{s}\), would cover in 1 year. ( \(a\) ) Express the distance from Earth to the Sun in parsecs and in light-years. (b) Express a light-year and a parsec in kilometers. Although the light-year is much used in popular writing, the parsec is the unit preferred by astronomers.

The stability of the cesium clock used as an atomic time standard is such that two cesium clocks would gain or lose \(1 \mathrm{~s}\) with respect to each other in about \(300,000 \mathrm{y}\). If this same precision were applied to the distance between New York and San Francisco ( \(2572 \mathrm{mi}\) ), by how much would successive measurements of this distance tend to differ?

Antarctica is roughly semicircular in shape with a radius of \(2000 \mathrm{~km}\). The average thickness of the ice cover is \(3000 \mathrm{~m}\). How many cubic centimeters of ice does Antarctica contain? (Ignore the curvature of the Earth.)

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