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Assuming that the length of the day uniformly increases by \(0.001 \mathrm{~s}\) in a century, calculate the cumulative effect on the measure of time over 20 centuries. Such a slowing down of the Earth's rotation is indicated by observations of the occurrences of solar eclipses during this period.

Short Answer

Expert verified
The cumulative effect on the measure of time over 20 centuries is 0.02 seconds.

Step by step solution

01

Understand the problem

Here, it is given that the length of the day increases by \(0.001 \mathrm{s}\) every century. That means each century, an extra \(0.001 \mathrm{s}\) is added to a day. If this effect is being accumulated over 20 centuries, we need to find out how much extra time has been added in total after 20 centuries.
02

Calculate the extra time added in every single century

It's given that the day length increases by \(0.001 \mathrm{s}\) each century. So in one century, the extra time added to a day is \(0.001 \mathrm{s}\).
03

Calculate the cumulative effect over 20 centuries

To calculate the total extra time added over 20 centuries, we multiply the extra time per century by the number of centuries. This gives us: \(0.001 \mathrm{s} \times 20 = 0.02 \mathrm{s}\). So over a period of 20 centuries, 0.02 seconds would have been added to the length of a day due to this slowing effect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Day Length Increase
The concept of day length increase refers to the gradual addition of time to each day over extended periods. In this context, it's significant that each century, the length of a day increases by a minuscule amount - exactly 0.001 seconds. This change might seem trivial in a single century. However, when accumulated over many centuries, this small increment becomes much more substantial. Understanding this initial increase is crucial. It forms the basis for calculating more extensive temporal changes over longer periods. This increase is primarily attributed to changes in Earth's rotation due to various factors like gravitational interactions with the Moon.
Cumulative Time Effect
The cumulative time effect stems from the consistent addition of time to each day due to the increased length. Over many centuries, these small additions accumulate into a noticeable effect. For example, over the course of 20 centuries, the total extra time added is calculated by multiplying the increase of 0.001 seconds per century by 20, resulting in a total of 0.02 seconds. This cumulative increase might not seem significant at first glance. However, when considering historical and geological timescales, it has critical implications. It can influence various natural and astronomical events, such as eclipses and tides, and impact long-term timekeeping.
Solar Eclipses Timing
The tiny yet consistent elongation of days can have intriguing effects on astronomical events, such as solar eclipses. Solar eclipses rely on precise timing between Earth’s rotation and the Moon’s orbit. Any change in day length over centuries can alter the expected timing of these eclipses. As the Earth's rotation slows, eclipses occur slightly later than they would have if the speed remained constant. Ancient records of solar eclipses provide significant historical data. This information helps scientists confirm how much the rotation has slowed over centuries and refine predictions. Observations of these eclipses serve as an essential tool in understanding the long-term changes in Earth's rotational dynamics.
Slowing of Earth's Rotation
The slowing of Earth's rotation is a gradual process influenced by external forces, primarily due to gravitational interactions, mainly with the Moon. This phenomenon is known as tidal friction. As a result, Earth's rotation speed decreases, leading to longer days. Tidal friction slows Earth's rotation by converting some of its rotational energy into heat. This process also causes the Moon to slowly move away from Earth, affecting both bodies' dynamics. Over centuries, the cumulative effect of this slow-down is measurable and forms the basis for studying the longer-term dynamics of Earth’s rotational history. In a practical sense, observing the slowing down helps refine calendars and ensures precise synchronization of technological systems. This knowledge assists scientists in developing accurate models for past and future Earth system behaviors.

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Most popular questions from this chapter

Astronomical distances are so large compared to terrestrial ones that much larger units of length are used for easy comprehension of the relative distances of astronomical objects. An astronomical unit \((\mathrm{AU})\) is equal to the average distance from Earth to the Sun, \(1.50 \times 10^{8} \mathrm{~km}\). A parsec (pc) is the distance at which 1 AU would subtend an angle of 1 second of arc. A light-year (ly) is the distance that light, traveling through a vacuum with a speed of \(3.00 \times 10^{5} \mathrm{~km} / \mathrm{s}\), would cover in 1 year. ( \(a\) ) Express the distance from Earth to the Sun in parsecs and in light-years. (b) Express a light-year and a parsec in kilometers. Although the light-year is much used in popular writing, the parsec is the unit preferred by astronomers.

(a) In track meets both 100 yards and 100 meters are used as distances for dashes. Which is longer? By how many meters is it longer? By how many feet? (b) Track and field records are kept for the mile and the so-called metric mile \((1500 \mathrm{me}-\) ters). Compare these distances.

A unit of area, often used in expressing areas of land, is the hectare, defined as \(10^{4} \mathrm{~m}^{2}\). An open-pit coal mine consumes 77 hectares of land, down to a depth of \(26 \mathrm{~m}\), each year. What volume of earth, in cubic kilometers, is removed in this time?

Enrico Fermi once pointed out that a standard lecture period \((50 \mathrm{~min})\) is close to 1 microcentury. How long is a microcentury in minutes, and what is the percentage difference from Fermi's approximation?

Earth is approximately a sphere of radius \(6.37 \times 10^{6} \mathrm{~m} .(a)\) What is its circumference in kilometers? (b) What is its surface area in square kilometers? ( \(c\) ) What is its volume in cubic kilometers?

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