Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A \(58-\) kg astronaut is in space, far from any objects that would exert a significant gravitational force on him. He would like to move toward his spaceship, but his jet pack is not functioning. He throws a 720 -g socket wrench with a velocity of \(5.0 \mathrm{m} / \mathrm{s}\) in a direction away from the ship. After \(0.50 \mathrm{s}\), he throws a 800 -g spanner in the same direction with a speed of \(8.0 \mathrm{m} / \mathrm{s} .\) After another $9.90 \mathrm{s}\(, he throws a mallet with a speed of \)6.0 \mathrm{m} / \mathrm{s}$ in the same direction. The mallet has a mass of \(1200 \mathrm{g}\) How fast is the astronaut moving after he throws the mallet?

Short Answer

Expert verified
Answer: The final velocity of the astronaut after throwing all the tools is approximately \(0.297 \, m/s\) towards the spaceship.

Step by step solution

01

Calculate the initial momentum of the astronaut-tool system.

Initially, the astronaut and all the tools are at rest. Therefore, the initial momentum of the system is 0.
02

Calculate the change in momentum during the first throw

The astronaut throws a 720 g socket wrench with a velocity of \(5.0m/s\) away from the ship. The change in momentum can be calculated using the formula \(\Delta p = m_{tool}v_{tool}\). Note that 720 g is equal to 0.72 kg. \(\Delta p_1 = (0.72 kg)(5.0 m/s) = 3.6 kg.m/s\)
03

Calculate the change in momentum during the second throw

The astronaut throws a 800 g spanner with a velocity of \(8.0m/s\) away from the ship. Similarly, we calculate the change in momentum using the same formula. Convert 800 g to 0.8 kg. \(\Delta p_2 = (0.8 kg)(8.0 m/s) = 6.4 kg.m/s\)
04

Calculate the change in momentum during the third throw

The astronaut throws a 1200 g mallet with a velocity of \(6.0m/s\) away from the ship. Again, calculate the change in momentum using the same formula. Convert 1200 g to 1.2 kg. \(\Delta p_3 = (1.2 kg)(6.0 m/s) = 7.2 kg.m/s\)
05

Calculate the total change in momentum

Add the change in momentum during each throw to find the total change in momentum. \(\Delta p_{total} = \Delta p_1 + \Delta p_2 + \Delta p_3 = 3.6 kg.m/s + 6.4 kg.m/s + 7.2 kg.m/s = 17.2 kg.m/s\)
06

Calculate the final velocity of the astronaut

Divide the total change in momentum by the astronaut's mass to find the final velocity of the astronaut. \(v_{astronaut} = \frac{\Delta p_{total}}{m_{astronaut}} = \frac{17.2 kg.m/s}{58 kg} = 0.2966 m/s\) The final velocity of the astronaut after throwing the mallet is approximately \(0.297 \, m/s\) towards the spaceship.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A BMW of mass \(2.0 \times 10^{3} \mathrm{kg}\) is traveling at $42 \mathrm{m} / \mathrm{s} .\( It approaches a \)1.0 \times 10^{3} \mathrm{kg}$ Volkswagen going \(25 \mathrm{m} / \mathrm{s}\) in the same direction and strikes it in the rear. Neither driver applies the brakes. Neglect the relatively small frictional forces on the cars due to the road and due to air resistance. (a) If the collision slows the BMW down to \(33 \mathrm{m} / \mathrm{s},\) what is the speed of the \(\mathrm{VW}\) after the collision? (b) During the collision, which car exerts a larger force on the other, or are the forces equal in magnitude? Explain.
An object of mass \(3.0 \mathrm{kg}\) is projected into the air at a \(55^{\circ}\) angle. It hits the ground 3.4 s later. What is its change in momentum while it is in the air? Ignore air resistance.
A radium nucleus (mass 226 u) at rest decays into a radon nucleus (symbol Rn, mass 222 u) and an alpha particle (symbol \(\alpha,\) mass 4 u). (a) Find the ratio of the speeds \(v_{\alpha} / v_{\mathrm{Rn}}\) after the decay. (b) Find the ratio of the magnitudes of the momenta \(p_{\alpha} / p_{\mathrm{Rn}^{*}}\) (c) Find the ratio of the kinetic energies \(K_{\alpha} / K_{\mathrm{Rn}} .\) (Note: "u" is a unit of mass; it is not necessary to convert it to kg.)
A marksman standing on a motionless railroad car fires a gun into the air at an angle of \(30.0^{\circ}\) from the horizontal. The bullet has a speed of $173 \mathrm{m} / \mathrm{s}\( (relative to the ground) and a mass of \)0.010 \mathrm{kg} .\( The man and car move to the left at a speed of \)1.0 \times 10^{-3} \mathrm{m} / \mathrm{s}$ after he shoots. What is the mass of the man and car? (See the hint in Problem 25.)
Two pendulum bobs have equal masses and lengths \((5.1 \mathrm{m}) .\) Bob \(\mathrm{A}\) is initially held horizontally while bob \(\mathrm{B}\) hangs vertically at rest. Bob A is released and collides elastically with bob B. How fast is bob B moving immediately after the collision?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free