Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A person climbs from a Paris metro station to the street level by walking up a stalled escalator in 94 s. It takes \(66 \mathrm{s}\) to ride the same distance when standing on the escalator when it is operating normally. How long would it take for him to climb from the station to the street by walking up the moving escalator?

Short Answer

Expert verified
Answer: It would take approximately 38.58 seconds for the person to climb from the station to the street by walking up the moving escalator.

Step by step solution

01

Assign variables

Let's assign variables for given data: - \(T_w\): the time it takes to walk up the stalled escalator, \(T_w=94\) s - \(T_r\): the time it takes to ride the same distance when the escalator is working, \(T_r=66\) s - \(T_\text{total}\): the time we need to find out for the person to climb from the station to the street by walking up the moving escalator
02

Calculate the distance

Since the distance covered in both cases is the same, we can denote this by the variable \(D\). To find this value, we can use the relationship: \(D = S_w \times T_w\) and \(D = S_e \times T_r\), where \(S_w\) is the person's walking speed and \(S_e\) is the escalator's speed. We can rewrite the equation as: \(S_w = \frac{D}{T_w}\) and \(S_e = \frac{D}{T_r}\)
03

Calculate the relative speed

When the person is walking up the moving escalator, their total speed would be the sum of their walking speed and the escalator's speed because they are moving in the same direction. We can write this as: \(S_\text{total} = S_w + S_e\) Substitute the values for speed from Step 2: \(S_\text{total} = \frac{D}{T_w} + \frac{D}{T_r}\)
04

Calculate the time it takes to climb by walking up the moving escalator

Now we can use the relationship distance = speed × time to find the total time taken by the person while walking up the moving escalator: \(T_\text{total} = \frac{D}{S_\text{total}}\) Substitute the expression for \(S_\text{total}\) from Step 3: \(T_\text{total} = \frac{D}{\frac{D}{T_w} + \frac{D}{T_r}}\) Note that we can cancel the \(D\) variable from the equation: \(T_\text{total} = \frac{1}{\frac{1}{T_w} + \frac{1}{T_r}}\) Plug in the values of \(T_w\) and \(T_r\): \(T_\text{total} = \frac{1}{\frac{1}{94\,\text{s}} + \frac{1}{66\,\text{s}}}\)
05

Calculate the final answer

We can now compute the value for \(T_\text{total}\): \(T_\text{total} = \frac{1}{\frac{94 + 66}{94 \times 66}} = \frac{94 \times 66}{94 + 66} = 38.579\) s Rounded to two decimal places, it would take approximately \(\boldsymbol{38.58}\) seconds for the person to climb from the station to the street by walking up the moving escalator.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A helicopter is flying horizontally at \(8.0 \mathrm{m} / \mathrm{s}\) and an altitude of \(18 \mathrm{m}\) when a package of emergency medical supplies is ejected horizontally backward with a speed of \(12 \mathrm{m} / \mathrm{s}\) relative to the helicopter. Ignoring air resistance, what is the horizontal distance between the package and the helicopter when the package hits the ground?
Vector \(\overrightarrow{\mathbf{a}}\) has components $a_{x}=-3.0 \mathrm{m} / \mathrm{s}^{2}\( and \)a_{y}=\( \)+4.0 \mathrm{m} / \mathrm{s}^{2} .$ (a) What is the magnitude of \(\overrightarrow{\mathbf{a}} ?\) (b) What is the direction of \(\overrightarrow{\mathbf{a}}\) ? Give an angle with respect to one of the coordinate axes.
A bicycle travels \(3.2 \mathrm{km}\) due east in \(0.10 \mathrm{h}\), then $4.8 \mathrm{km}\( at \)15.0^{\circ}\( east of north in \)0.15 \mathrm{h},$ and finally another \(3.2 \mathrm{km}\) due east in \(0.10 \mathrm{h}\) to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
A runner times his speed around a track with a circumference of $0.50 \mathrm{mi} .\( He finds that he has run a distance of \)1.00 \mathrm{mi}$ in 4.0 min. What is his (a) average speed and (b) average velocity magnitude in \(\mathrm{m} / \mathrm{s}\) ?
A speedboat heads west at \(108 \mathrm{km} / \mathrm{h}\) for 20.0 min. It then travels at \(60.0^{\circ}\) south of west at \(90.0 \mathrm{km} / \mathrm{h}\) for 10.0 min. (a) What is the average speed for the trip? (b) What is the average velocity for the trip?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free