Question

Write the symbol (in the form \(_{Z}^{A} \mathrm{X}\) ) for the nuclide with 38 protons and 50 neutrons and identify the element.

Short answer

Answer: The nuclide symbol for an atom with 38 protons and 50 neutrons is \(_{38}^{88}\mathrm{Sr}\), and it represents the element Strontium.

Step-by-step solution

Determine the element with the atomic number of 38

Referring to the periodic table, find the element with 38 protons. In this case, it is Strontium (Sr).

Calculate the mass number

Calculate the mass number (A) by adding the number of protons and neutrons together: A = number of protons + number of neutrons = 38 + 50 = 88

Write the nuclide symbol

Now that we have found the element, and calculated the mass number, we can write the nuclide symbol as follows: \(_{38}^{88}\mathrm{Sr}\) So, the symbol for the nuclide with 38 protons and 50 neutrons is \(_{38}^{88}\mathrm{Sr}\), and the element is Strontium.