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What is the binding energy of an \(\alpha\) particle (a \(^{4} \mathrm{He}\) nucleus)? The mass of an \(\alpha\) particle is \(4.00151 \mathrm{u}\).

Short Answer

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Question: Calculate the binding energy of an α particle with a mass of 4.00151 atomic mass units. Answer: To calculate the binding energy of the α particle, follow these steps: 1. Determine the mass of the individual nucleons in the α particle (two protons and two neutrons). 2. Calculate the mass defect by finding the difference between the total mass of the individual nucleons and the mass of the α particle. 3. Convert the mass defect into energy using Einstein's equation \(E = mc^2\). 4. Convert the energy to megaelectronvolts (MeV) using the appropriate conversion factors. By following these steps, you can find the binding energy of the α particle in MeV.

Step by step solution

01

Determine the mass of the individual nucleons

First, we need to find the mass of the individual nucleons in the α particle. In an α particle, there are two protons and two neutrons. The mass of a proton is approximately 1.00728 u, and the mass of a neutron is approximately 1.00867 u. So, we can calculate the total mass of the nucleons as follows: Total mass of nucleons = (2 × mass of a proton) + (2 × mass of a neutron)
02

Calculate the mass defect

Next, we will calculate the mass defect, which is the difference between the total mass of the individual nucleons and the mass of the α particle. Given that the mass of the α particle is 4.00151 u, we can calculate the mass defect as follows: Mass defect = Total mass of nucleons - Mass of α particle
03

Convert the mass defect into energy

Now we'll convert the mass defect we found in the previous step into energy using Einstein's equation \(E = mc^2\). Note that we must first convert the mass defect from atomic mass units (u) to kilograms (kg) using the following conversion factor: 1 u = 1.660539 x \(10^{-27}\) kg. Once converted, we can then calculate the energy in joules (J) as follows: Energy = Mass defect (in kg) × \((3.0 \times 10^8 m/s)^2\)
04

Convert the energy to MeV

Finally, we need to convert the energy found in the previous step from joules (J) to megaelectronvolts (MeV), which is a more commonly used unit for binding energy. To do this, we will use the following conversion factor: 1 J = 6.242 x \(10^{12}\) MeV. So, the binding energy will be: Binding energy = Energy (in J) × conversion factor Following these steps, you will be able to find the binding energy of the α particle in MeV.

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Most popular questions from this chapter

Radon gas (Rn) is produced by the \(\alpha\) decay of radium 226 88 28 A How many neutrons and how many protons are present in the nucleus of the isotope of Rn produced by this decay? (b) In the air in an average size room in a student basement apartment in Ithaca, NY, there are about \(10^{7}\) Rn nuclei. The Rn nucleus itself is radioactive; it too decays by emitting an \(\alpha\) particle. The half-life of Rn is 3.8 days. How many \(\alpha\) particles per second are emitted by decaying Rn nuclei in the room?
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