Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The energy to accelerate a starship comes from combining matter and antimatter. When this is done the total rest energy of the matter and antimatter is converted to other forms of energy. Suppose a starship with a mass of \(2.0 \times 10^{5} \mathrm{kg}\) accelerates to \(0.3500 c\) from rest. How much matter and antimatter must be converted to kinetic energy for this to occur?

Short Answer

Expert verified
Answer: To calculate the amount of matter and antimatter required, follow these steps: 1. Calculate the Lorentz factor, γ, using the formula: γ = 1 / sqrt(1 - (v^2 / c^2)). For a speed of 0.3500c, γ is approximately 1.1843. 2. Calculate the final kinetic energy, K, using the formula: K = (γ - 1) * mc^2. With the mass of the starship given as 2.0 x 10^5 kg, K is approximately 4.667 x 10^18 Joules. 3. Find the amount of matter and antimatter, Δm, using the equation: Δm = K / c^2. The required amount of matter and antimatter is approximately 5.185 x 10^10 kg.

Step by step solution

01

Find the final kinetic energy of the starship

First, we need to calculate the final kinetic energy of the starship using the relativistic kinetic energy formula, which is given by: \(K = ( \gamma - 1)mc^2\) where \(K\) is the kinetic energy, \(\gamma\) is the Lorentz factor, \(m\) is the mass of the object, and \(c\) is the speed of light. The Lorentz factor is given by: \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\) Given that \(m = 2.0 \times 10^5 \mathrm{kg},\ v = 0.3500c\). We will first calculate the Lorentz factor and then find the kinetic energy.
02

Calculate the Lorentz factor

We have the formula for the Lorentz factor: \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\) Substituting the values, we get: \(\gamma = \frac{1}{\sqrt{1-(0.3500)^2}}\) Solve for \(\gamma\).
03

Calculate the kinetic energy

Now that we have the Lorentz factor, we can find the kinetic energy using the relativistic kinetic energy formula: \(K = ( \gamma - 1)mc^2\) Substitute the values: \(K = (\gamma - 1)(2.0 \times 10^5 \mathrm{kg})(3.0 \times 10^8 \mathrm{m/s})^2\) Solve for \(K\).
04

Find the amount of matter and antimatter

The total amount of matter and antimatter converted is equal to the total kinetic energy of the starship. We can find this using the rest energy equation: \(E = mc^2\) We already know the value of \(K\) and \(c\). Let's implement the equation like this: \(K = (\Delta m) c^2\) Now we need to solve for \(\Delta m\): \(\Delta m = \frac{K}{c^2}\) Substitute the values of \(K\) and \(c\) to find the required amount of matter and antimatter.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An astronaut has spent a long time in the Space Shuttle traveling at $7.860 \mathrm{km} / \mathrm{s} .$ When he returns to Earth, he is 1.0 s younger than his twin brother. How long was he on the shuttle? [Hint: Use an approximation from Appendix A.5 and beware of calculator round off errors.]
A spaceship is moving away from Earth with a constant velocity of \(0.80 c\) with respect to Earth. The spaceship and an Earth station synchronize their clocks, setting both to zero, at an instant when the ship is near Earth. By prearrangement, when the clock on Earth reaches a reading of $1.0 \times 10^{4} \mathrm{s}$, the Earth station sends out a light signal to the spaceship. (a) In the frame of reference of the Earth station, how far must the signal travel to reach the spaceship? (b) According to an Earth observer, what is the reading of the clock on Earth when the signal is received?
A lambda hyperon \(\Lambda^{0}\) (mass \(=1115.7 \mathrm{MeV} / \mathrm{c}^{2}\) ) at rest in the lab frame decays into a neutron \(n\) (mass \(=\) $939.6 \mathrm{MeV} / c^{2}\( ) and a pion (mass \)=135.0 \mathrm{MeV} / c^{2}$ ): $$\Lambda^{0} \rightarrow \mathrm{n}+\pi^{0}$$ What are the kinetic energies (in the lab frame) of the neutron and pion after the decay? [Hint: Use Eq. \((26-11)\) to find momentum.]
An electron has a total energy of 6.5 MeV. What is its momentum (in MeV/c)?
A spaceship passes over an observation station on Earth. Just as the nose of the ship passes the station, a light in the nose of the ship flashes. As the tail of the ship passes the station, a light flashes in the ship's tail. According to an Earth observer, 50.0 ns elapses between the two events. In the astronaut's reference frame, the length of the ship is \(12.0 \mathrm{m} .\) (a) How fast is the ship traveling according to an Earth observer? (b) What is the elapsed time between light flashes in the astronaut's frame of reference?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free