Question

A slide projector, using slides of width \(5.08 \mathrm{cm},\) produces an image that is \(2.00 \mathrm{m}\) wide on a screen \(3.50 \mathrm{m}\) away. What is the focal length of the projector lens?

Short answer

#tag_title# Step 2: Convert the units. #tag_content# To make all the units consistent, let's convert the image width and image distance to centimeters: - Image width: \(2.00 \mathrm{m} = 200 \mathrm{cm}\) - Image distance: \(3.50 \mathrm{m} = 350 \mathrm{cm}\) Now we have: - Object width (width of the slide) \(= 5.08 \mathrm{cm}\) - Image width \(= 200 \mathrm{cm}\) - Image distance \(= 350 \mathrm{cm}\)

Step-by-step solution

Write down the known values.

We are given the following information: - Object width (width of the slide) \(= 5.08 \mathrm{cm}\) - Image width \(= 2.00 \mathrm{m}\) - Distance between the projector lens and the screen (image distance) \(= 3.50 \mathrm{m}\)