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The distance from the lens system (cornea + lens) of a particular eye to the retina is \(1.75 \mathrm{cm} .\) What is the focal length of the lens system when the eye produces a clear image of an object \(25.0 \mathrm{cm}\) away?

Short Answer

Expert verified
Answer: The focal length is approximately \(1.636 \mathrm{cm}\).

Step by step solution

01

Understand the Lens Formula

Using the lens formula, we can determine the focal length of the lens system. The formula is: \[\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}\] where: - \(f\) is the focal length of the lens system, - \(d_o\) is the distance from the object to the lens system, and - \(d_i\) is the distance from the lens system to the image (or the distance from the lens system to the retina). Given that the image is formed exactly on the retina, we can use the distance from the lens system to the retina as \(d_i\).
02

Substitute the given values

We know that the distance from the object to the eye (\(d_o\)) is \(25.0 \mathrm{cm}\), and the distance from the lens system to the retina (\(d_i\)) is \(1.75 \mathrm{cm}\). Substitute these values into the lens formula: \[\frac{1}{f} = \frac{1}{25.0 \mathrm{cm}} + \frac{1}{1.75 \mathrm{cm}}\]
03

Calculate the focal length

To find the focal length \(f\), first compute the sum of the fractions and then find the inverse: \[\frac{1}{f} = 0.04 \mathrm{cm^{-1}}+0.5714 \mathrm{cm^{-1}}\] \[\frac{1}{f} = 0.6114 \mathrm{cm^{-1}}\] \[f = \frac{1}{0.6114 \mathrm{cm^{-1}}}\]
04

Find the final answer

Calculate the focal length of the lens system: \[f \approx 1.636 \mathrm{cm}\] The focal length of the lens system when the eye produces a clear image of an object \(25.0 \mathrm{cm}\) away is approximately \(1.636 \mathrm{cm}\).

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Most popular questions from this chapter

Kim says that she was less than 10 ft away from the president when she took a picture of him with her \(50-\mathrm{mm}\) focal length camera lens. The picture shows the upper half of the president's body (or \(3.0 \mathrm{ft}\) of his total height). On the negative of the film, this part of his body is $18 \mathrm{mm}$ high. How close was Kim to the president when she took the picture?
A nearsighted man cannot clearly see objects more than \(2.0 \mathrm{m}\) away. The distance from the lens of the eye to the retina is \(2.0 \mathrm{cm},\) and the eye's power of accommodation is \(4.0 \mathrm{D}\) (the focal length of the cornea-lens system increases by a maximum of \(4.0 \mathrm{D}\) over its relaxed focal length when accommodating for nearby objects). (a) As an amateur optometrist, what corrective eyeglass lenses would you prescribe to enable him to clearly see distant objects? Assume the corrective lenses are $2.0 \mathrm{cm}$ from the eyes. (b) Find the nearest object he can see clearly with and without his glasses.

Two converging lenses are placed \(88.0 \mathrm{cm}\) apart. An object is placed \(1.100 \mathrm{m}\) to the left of the first lens. which has a focal length of \(25.0 \mathrm{cm} .\) The final image is located \(15.0 \mathrm{cm}\) to the right of the second lens. (a) What is the focal length of the second lens? (b) What is the total magnification?

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The wing of an insect is \(1.0 \mathrm{mm}\) long. When viewed through a microscope, the image is \(1.0 \mathrm{m}\) long and is located \(5.0 \mathrm{m}\) away. Determine the angular magnification.
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