Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An ac series circuit containing a capacitor, inductor, and resistance is found to have a current of amplitude \(0.50 \mathrm{A}\) for a source voltage of amplitude \(10.0 \mathrm{V}\) at an angular frequency of $200.0 \mathrm{rad} / \mathrm{s} .\( The total resistance in the circuit is \)15.0 \Omega$ (a) What are the power factor and the phase angle for the circuit? (b) Can you determine whether the current leads or lags the source voltage? Explain.

Short Answer

Expert verified
Based on the given information and calculations for this circuit: a) The power factor is 0.75, and the phase angle between the voltage and current is 41.4 degrees. b) It is not possible to determine whether the current leads or lags the source voltage without more information about the inductor and capacitor values in the circuit.

Step by step solution

01

Calculate impedance amplitude

The Impedance (Z) of the circuit can be found using the given amplitude of Voltage(V) and Current(I) using, \(Z =\frac{V}{I}\). So, plug in the given values to get the Impedance (Z) of the circuit. $$Z = \frac{10.0 V}{0.50 A} = 20.0 \,\Omega !$$
02

Calculate reactance amplitude

Next, we find the amplitude of the reactance (X). We are given the resistance (R) in the circuit and we have calculated impedance (Z), so we can use the following formula to find the reactance (X): $$X = \sqrt{Z^2 - R^2}$$ where X is the reactance, Z is impedance, and R is resistance. $$X = \sqrt{(20.0 \, \Omega)^2 - (15.0 \, \Omega)^2} = \sqrt{625} \, \Omega$$ $$X = 25.0 \, \Omega$$
03

Calculate the power factor

Now that we have the impedance (Z) and resistance (R), we can calculate the power factor (PF) of the circuit using the following formula: $$PF = \frac{R}{Z}$$ $$PF = \frac{15.0 \, \Omega}{20.0 \, \Omega} = 0.75$$
04

Calculate the phase angle

Using the power factor, we can calculate the phase angle (θ) between the voltage and current using: $$\cos{\theta} = PF$$ $$\theta = \arccos{(PF)}$$ $$\theta = \arccos{(0.75)} = 41.4°$$
05

Determine if current leads or lags the source voltage

The circuit contains a resistor, inductor, and capacitor. In an inductor, the current lags the voltage, and in a capacitor, the current leads the voltage. Since we are not told the values of the inductor (L) and capacitor (C), we cannot determine the net effect in this case. However, if the net effect was reactive (inductive or capacitive), the magnitude of the phase angle would have been exactly 90°. But the phase angle is 41.4° which is not exactly 90°. So, there must be some complex combination of inductor and capacitor effects that lead to a net phase angle of 41.4°. Hence, we cannot determine whether the current leads or lags the source voltage without more information. In conclusion: a) The power factor for the circuit is 0.75, and the phase angle is 41.4°. b) We cannot determine whether the current leads or lags the source voltage without more information on the inductor and capacitor values.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) What is the reactance of a \(10.0-\mathrm{mH}\) inductor at the frequency \(f=250.0 \mathrm{Hz} ?\) (b) What is the impedance of a series combination of the \(10.0-\mathrm{mH}\) inductor and a \(10.0-\Omega\) resistor at $250.0 \mathrm{Hz} ?$ (c) What is the maximum current through the same circuit when the ac voltage source has a peak value of \(1.00 \mathrm{V} ?\) (d) By what angle does the current lag the voltage in the circuit?
A computer draws an rms current of \(2.80 \mathrm{A}\) at an \(\mathrm{rms}\) voltage of \(120 \mathrm{V}\). The average power consumption is 240 W. (a) What is the power factor? (b) What is the phase difference between the voltage and current?
Finola has a circuit with a \(4.00-\mathrm{k} \Omega\) resistor, a \(0.750-\mathrm{H}\) inductor, and a capacitor of unknown value connected in series to a \(440.0-\mathrm{Hz}\) ac source. With an oscilloscope, she measures the phase angle to be \(25.0^{\circ} .\) (a) What is the value of the unknown capacitor? (b) Finola has several capacitors on hand and would like to use one to tune the circuit to maximum power. Should she connect a second capacitor in parallel across the first capacitor or in series in the circuit? Explain. (c) What value capacitor does she need for maximum power?
An \(R L C\) series circuit has a resistance of \(R=325 \Omega\) an inductance \(\quad L=0.300 \mathrm{mH}, \quad\) and \(\quad\) a capacitance $C=33.0 \mathrm{nF} .$ (a) What is the resonant frequency? (b) If the capacitor breaks down for peak voltages in excess of \(7.0 \times 10^{2} \mathrm{V},\) what is the maximum source voltage amplitude when the circuit is operated at the resonant frequency?
A capacitor (capacitance \(=C\) ) is connected to an ac power supply with peak voltage \(V\) and angular frequency \(\alpha\) (a) During a quarter cycle when the capacitor goes from being uncharged to fully charged, what is the average current (in terms of \(C . V\), and \(\omega\) )? [Hint: \(\left.i_{\mathrm{av}}=\Delta Q / \Delta t\right]\) (b) What is the rms current? (c) Explain why the average and rms currents are not the same.
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free