Question

When the emf for the primary of a transformer is of amplitude $5.00 \mathrm{V},\( the secondary emf is \)10.0 \mathrm{V}$ in amplitude. What is the transformer turns ratio \(\left(N_{2} / N_{1}\right) ?\)

Short answer

Answer: The transformer turns ratio (N2/N1) is 2.

Step-by-step solution

Understand the Transformer Turns Ratio Formula

The formula to relate the primary and secondary voltages of a transformer with its turns ratio is given by: \[ \frac{V_{2}}{V_{1}} = \frac{N_{2}}{N_{1}} \] where V1 is the primary voltage, V2 is the secondary voltage, N1 is the number of turns in the primary coil, and N2 is the number of turns in the secondary coil.

Plug in the given values

We are given V1 = 5.00 V and V2 = 10.0 V in the problem. We will plug these values into the formula: \[ \frac{10.0}{5.00} = \frac{N_{2}}{N_{1}} \]

Solve for N2/N1

Now, we will solve for the transformer turns ratio (N2/N1): \[ \frac{N_{2}}{N_{1}} = \frac{10.0}{5.00} = 2 \] So the transformer turns ratio N2/N1 is 2.