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A balloon contains \(200.0 \mathrm{L}\) of nitrogen gas at $20.0^{\circ} \mathrm{C}$ and at atmospheric pressure. How much energy must be added to raise the temperature of the nitrogen to \(40.0^{\circ} \mathrm{C}\) while allowing the balloon to expand at atmospheric pressure?

Short Answer

Expert verified
Answer: Approximately 4760 J of energy are required.

Step by step solution

01

Calculate the number of moles of nitrogen gas

Using the Ideal Gas Law, \(PV = nRT\), we can calculate the number of moles \(n\) of nitrogen gas inside the balloon. Firstly, we need to convert the temperature from Celsius to Kelvin, \(T_i = 20.0^{\circ} \mathrm{C} + 273.15 \mathrm{K} = 293.15 \mathrm{K}\) and \(T_f = 40.0^{\circ} \mathrm{C} + 273.15 \mathrm{K} = 313.15 \mathrm{K}\). Given \(V = 200.0 \mathrm{L}\), \(T_i = 293.15 \mathrm{K}\), and \(P = 1 \mathrm{atm}\). Then we have \(1 \mathrm{atm} \cdot 200.0 \mathrm{L} = n \cdot 0.0821 \frac{\mathrm{L.atm}}{\mathrm{K.mol}} \cdot 293.15 \mathrm{K}\) Rearranging and solving for \(n\) gives: $$n = \frac{1\mathrm{atm} \cdot 200.0\mathrm{L}}{0.0821 \frac{\mathrm{L.atm}}{\mathrm{K.mol}} \cdot 293.15\mathrm{K}}$$ $$n \approx 8.17 \mathrm{mol}$$
02

Calculate energy using the heat capacity

Now we will use the energy equation \(q = n C_p \Delta T\) to calculate the amount of energy required to raise the temperature from \(T_i = 293.15\mathrm{K}\) to \(T_f = 313.15\mathrm{K}\), while keeping the pressure constant. Recall that for diatomic gases, the specific heat capacity under constant pressure is \(C_p = \frac{7}{2} R \approx 29.1 \frac{\mathrm{J}}{\mathrm{mol.K}}\). The temperature difference is \(\Delta T = T_f - T_i = 313.15\mathrm{K} - 293.15\mathrm{K} = 20.0\mathrm{K}\). Using the energy equation with \(n \approx 8.17 \mathrm{mol}\), \(C_p \approx 29.1 \frac{\mathrm{J}}{\mathrm{mol.K}}\), and \(\Delta T = 20.0\mathrm{K}\), we get: $$q = 8.17 \mathrm{mol} \cdot 29.1 \frac{\mathrm{J}}{\mathrm{mol.K}} \cdot 20.0\mathrm{K}$$ $$q \approx 4760 \mathrm{J}$$ So, approximately 4760 J of energy must be added to raise the temperature of the nitrogen to \(40.0^{\circ} \mathrm{C}\) while allowing the balloon to expand at atmospheric pressure.

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Most popular questions from this chapter

A \(0.50-\mathrm{kg}\) block of iron $[c=0.44 \mathrm{kJ} /(\mathrm{kg} \cdot \mathrm{K})]\( at \)20.0^{\circ} \mathrm{C}$ is in contact with a \(0.50-\mathrm{kg}\) block of aluminum \([c=\) $0.900 \mathrm{kJ} /(\mathrm{kg} \cdot \mathrm{K})]$ at a temperature of \(20.0^{\circ} \mathrm{C} .\) The system is completely isolated from the rest of the universe. Suppose heat flows from the iron into the aluminum until the temperature of the aluminum is \(22.0^{\circ} \mathrm{C}\) (a) From the first law, calculate the final temperature of the iron. (b) Estimate the entropy change of the system. (c) Explain how the result of part (b) shows that this process is impossible. [Hint: since the system is isolated, $\left.\Delta S_{\text {System }}=\Delta S_{\text {Universe }} .\right]$

A large, cold \(\left(0.0^{\circ} \mathrm{C}\right)\) block of iron is immersed in a tub of hot \(\left(100.0^{\circ} \mathrm{C}\right)\) water. In the first \(10.0 \mathrm{s}, 41.86 \mathrm{kJ}\) of heat are transferred, although the temperatures of the water and the iron do not change much in this time. Ignoring heat flow between the system (iron + water) and its surroundings, calculate the change in entropy of the system (iron + water) during this time.

How much heat does a heat pump with a coefficient of performance of 3.0 deliver when supplied with \(1.00 \mathrm{kJ}\) of electricity?

On a hot day, you are in a sealed, insulated room. The room contains a refrigerator, operated by an electric motor. The motor does work at the rate of \(250 \mathrm{W}\) when it is running. Assume the motor is ideal (no friction or electrical resistance) and that the refrigerator operates on a reversible cycle. In an effort to cool the room, you turn on the refrigerator and open its door. Let the temperature in the room be \(320 \mathrm{K}\) when this process starts, and the temperature in the cold compartment of the refrigerator be \(256 \mathrm{K}\). At what net rate is heat added to \((+)\) or \(\mathrm{sub}\) tracted from \((-)\) the room and all of its contents?

The efficiency of an engine is \(0.21 .\) For every \(1.00 \mathrm{kJ}\) of heat absorbed by the engine, how much (a) net work is done by it and (b) heat is released by it?
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