Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How much heat is required to raise the body temperature of a \(50.0-\mathrm{kg}\) woman from \(37.0^{\circ} \mathrm{C}\) to $38.4^{\circ} \mathrm{C} ?$

Short Answer

Expert verified
Question: Calculate the heat required to raise the body temperature of a 50.0 kg woman from 37.0°C to 38.4°C. Assume the specific heat capacity of the human body is approximately the same as that of water (4.18 J/g°C). Answer: The heat required to raise the body temperature of a 50.0 kg woman from 37.0°C to 38.4°C is 292,600 J.

Step by step solution

01

List the given values

Mass (m) = 50.0 kg, initial temperature (T1) = 37.0°C, final temperature (T2) = 38.4°C, specific heat capacity (c) = 4.18 J/g°C
02

Calculate the temperature change

ΔT = T2 - T1 = 38.4°C - 37.0°C = 1.4°C
03

Convert mass from kg to grams

1 kg = 1000 g, so 50.0 kg = 50.0 * 1000 = 50000 g
04

Calculate the heat (Q)

Use the formula Q = mcΔT. Plug in the values: Q = (50000 g) * (4.18 J/g°C) * (1.4°C) Q = 292600 J
05

Present the final answer

The heat required to raise the body temperature of a 50.0 kg woman from 37.0°C to 38.4°C is 292,600 J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ice at \(0.0^{\circ} \mathrm{C}\) is mixed with \(5.00 \times 10^{2} \mathrm{mL}\) of water at \(25.0^{\circ} \mathrm{C} .\) How much ice must melt to lower the water temperature to \(0.0^{\circ} \mathrm{C} ?\)

A heating coil inside an electric kettle delivers \(2.1 \mathrm{kW}\) of electric power to the water in the kettle. How long will it take to raise the temperature of \(0.50 \mathrm{kg}\) of water from \(20.0^{\circ} \mathrm{C}\) to \(100.0^{\circ} \mathrm{C} ?\) (tutorial: heating)
A stainless steel saucepan, with a base that is made of \(0.350-\mathrm{cm}-\) thick steel \([\kappa=46.0 \mathrm{W} /(\mathrm{m} \cdot \mathrm{K})]\) fused to a \(0.150-\mathrm{cm}\) thickness of copper $[\kappa=401 \mathrm{W} /(\mathrm{m} \cdot \mathrm{K})],\( sits on a ceramic heating element at \)104.00^{\circ} \mathrm{C} .\( The diameter of the pan is \)18.0 \mathrm{cm}$ and it contains boiling water at \(100.00^{\circ} \mathrm{C} .\) (a) If the copper-clad bottom is touching the heat source, what is the temperature at the copper-steel interface? (b) At what rate will the water evaporate from the pan?
You are given \(250 \mathrm{g}\) of coffee (same specific heat as water) at \(80.0^{\circ} \mathrm{C}\) (too hot to drink). In order to cool this to $\left.60.0^{\circ} \mathrm{C}, \text { how much ice (at } 0.0^{\circ} \mathrm{C}\right)$ must be added? Ignore heat content of the cup and heat exchanges with the surroundings.
A cylinder contains 250 L of hydrogen gas \(\left(\mathrm{H}_{2}\right)\) at \(0.0^{\circ} \mathrm{C}\) and a pressure of 10.0 atm. How much energy is required to raise the temperature of this gas to \(25.0^{\circ} \mathrm{C} ?\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free