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Chapter 1: Problem 30

A molecule in air is moving at a speed of \(459 \mathrm{m} / \mathrm{s}\). How many meters would the molecule move during \(7.00 \mathrm{ms}\) (milliseconds) if it didn't collide with any other molecules?

Short Answer

Expert verified
Answer: 3.213 meters

Step by step solution

01

Convert time to seconds

To convert the given time (7.00 ms) to seconds, we divide it by 1,000. Time in seconds = \(7.00 \mathrm{ms} \div 1000 = 0.007 \mathrm{s}\)
02

Calculate the distance

Use the distance formula (d = v * t) to calculate the distance the molecule would move during 0.007 seconds. d = \(459 \mathrm{m/s} * 0.007 \mathrm{s}\)
03

Compute the result

Multiply the speed by the time to obtain the distance. d = \(459 * 0.007 = 3.213 \mathrm{m}\) Hence, the molecule would move 3.213 meters during 7.00 milliseconds if it didn't collide with any other molecules.

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