Chapter 6: Problem 35
Calculate A \(0.14-\mathrm{kg}\) pinecone is \(16 \mathrm{~m}\) above the ground. What is its gravitational potential energy?
Short Answer
Expert verified
The gravitational potential energy is 21.95 J.
Step by step solution
01
Understanding the Problem
We need to find the gravitational potential energy (GPE) of a pinecone that is 16 meters above the ground and has a mass of 0.14 kg. Gravitational potential energy is given by the formula \[ GPE = m \cdot g \cdot h \]where \( m \) is mass, \( g \) is the acceleration due to gravity (approximated as \( 9.8 \ m/s^2 \)), and \( h \) is height.
02
Substituting the Values
Substitute the provided values into the formula. For the pinecone mass \( m = 0.14 \ kg \), \( g = 9.8 \ m/s^2 \), and \( h = 16 \ m \):\[ GPE = 0.14 \ kg \times 9.8 \ m/s^2 \times 16 \ m \]
03
Calculating the GPE
Perform the calculation by multiplying the values together:\( 0.14 \times 9.8 = 1.372 \).Then, multiply this result by the height:\( 1.372 \times 16 = 21.952 \).
04
Rounding the Result
Round the resulting gravitational potential energy value to two decimal places for precision. Thus, \[ GPE = 21.95 \ J \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Physics Problem-Solving
When it comes to physics problem-solving, the key is to break down the question into manageable parts. In the case of calculating gravitational potential energy, start by identifying what is given: mass, height, and the constant of gravity. Follow these steps:
- Understand the question: Here, identify what needs to be calculated - the gravitational potential energy of a pinecone.
- Know the formula: The formula for gravitational potential energy is \( GPE = m \cdot g \cdot h \).
- Substitute the values: Place provided values into the formula. For example, here \( m = 0.14 \ kg \), \( h = 16 \ m \), and \( g = 9.8 \ m/s^2 \).
- Calculate step by step: Multiply the mass by gravitational acceleration, then by the height.
- Round your answer appropriately: This ensures that your answer is not only correct but also presented neatly.
Acceleration Due to Gravity
Acceleration due to gravity, denoted as \( g \), is a fundamental concept in physics. It describes the rate at which objects accelerate towards the Earth due to gravitational pull.
This value is approximately \( 9.8 \ m/s^2 \) on Earth.
This value is approximately \( 9.8 \ m/s^2 \) on Earth.
- Uniformity of g: Accelerations can vary slightly based on location due to Earth's shape and rotation, but \( 9.8 \ m/s^2 \) is standard for calculation purposes.
- Effect on objects: This constant affects all objects in free fall equally, regardless of their mass.
- In the formula: In the potential energy formula \( GPE = m \cdot g \cdot h \), \( g \) helps determine the energy associated with an object's position.
Energy Calculation
Energy calculation involves understanding how energy is measured and converted. In our exercise, we find the potential energy a pinecone has based on its height above the ground.
Potential energy tells us how much work an object can potentially do due to its position.
Potential energy tells us how much work an object can potentially do due to its position.
- Gravitational Potential Energy: This form of energy increases with height and mass. It's calculated using \( GPE = m \cdot g \cdot h \).
- Unit of measurement: The result, in Joules, is a unit of energy. So, when the pinecone is dropped, it would eventually convert this energy into other forms like kinetic.
- Importance in calculations: Gravitational potential energy helps in understanding concepts like energy conservation and energy transition from potential to kinetic.
Physics Education
Physics education equips students with a framework to understand the natural world through principles and laws. It requires developing strong problem-solving skills and understanding of core concepts like energy and gravity.
Here's how these concepts are often taught:
Here's how these concepts are often taught:
- Conceptual understanding: Rather than relying solely on memorization, students are encouraged to understand the 'why' and 'how' behind formulas and phenomena.
- Hands-on learning: Experiments and real-life applications make learning engaging — like dropping objects to calculate potential energy.
- Mathematical skill development: Students improve their mathematical reasoning by working with formulas and solving physics problems.
- Interdisciplinary learning: Physics often combines knowledge from math, engineering, and technology, showing students the interconnectedness of scientific principles.