Chapter 6: Problem 140
An \(1865-\mathrm{kg}\) airplane starts at rest on an airport runway at sea level. What is the change in mechanical energy of the airplane if it climbs to a cruising altitude of \(2420 \mathrm{~m}\) and maintains a constant speed of \(96.5 \mathrm{~m} / \mathrm{s}\) ?
Short Answer
Expert verified
The change in mechanical energy of the airplane is approximately \( 52.9 \times 10^6 \text{ Joules} \).
Step by step solution
01
Calculate the Gravitational Potential Energy
The change in gravitational potential energy (GPE) when the airplane rises to a height \( h \) is given by the formula \( \Delta PE = mgh \), where \( m \) is mass, \( g \) is acceleration due to gravity \( (9.81\, \text{m/s}^2) \), and \( h \) is height. Substituting the given values, we have: \( \Delta PE = 1865\, \text{kg} \times 9.81\, \text{m/s}^2 \times 2420\, \text{m} \). Calculate \( \Delta PE \).
02
Substitute and Solve for Gravitational Potential Energy
Calculate \( \Delta PE \) using the equation: \( \Delta PE = 1865 \times 9.81 \times 2420 \). This results in \( \Delta PE = 44,244,693 \text{ Joules} \).
03
Calculate the Kinetic Energy
The kinetic energy (KE) can be calculated using the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity. Using the given constant speed of the airplane, \( KE = \frac{1}{2} \times 1865 \times (96.5)^2 \). Calculate \( KE \).
04
Substitute and Solve for Kinetic Energy
Substitute the values in the equation to find \( KE: KE = \frac{1}{2} \times 1865 \times 96.5^2 = 8,679,871.125 \text{ Joules} \).
05
Calculate the Total Change in Mechanical Energy
The total change in mechanical energy is the sum of the change in potential energy and the change in kinetic energy. That is, \( \Delta E_{total} = \Delta PE + KE \). Substitute the values: \( \Delta E_{total} = 44,244,693 + 8,679,871.125 \). Calculate \( \Delta E_{total} \).
06
Final Solution for Total Change in Mechanical Energy
Calculate the sum \( \Delta E_{total} = 44,244,693 + 8,679,871.125 = 52,924,564.125 \text{ Joules} \). Therefore, the change in mechanical energy of the airplane is approximately \( 52.9 \times 10^6 \text{ Joules} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Potential Energy
Gravitational potential energy (GPE) is a type of energy an object possesses because of its position relative to Earth. It's like having a reserve of energy stored due to gravity. When you lift an object, you're storing energy in it. The higher you lift it, the more energy gets stored. This energy depends on three main factors:
- Mass (\( m \))
- Height (\( h \))
- Gravitational acceleration (\( g \) which is typically \( 9.81 \) m/s²)
Kinetic Energy
Kinetic energy (KE) is the energy an object has due to its motion. If an object is moving, it has kinetic energy. The faster it moves, the more kinetic energy it possesses. The kinetic energy also depends on the object's mass. Here's how KE is calculated:\[KE = \frac{1}{2}mv^2\]This formula tells us that:
- The mass of the object (\( m \)) affects the kinetic energy linearly.
- The speed or velocity (\( v \)) of the object affects kinetic energy quadratically, meaning it has a squared effect.
Energy Conservation
Energy conservation is a fundamental principle in physics that helps us understand how energy remains constant in a closed system. It implies that energy cannot be created or destroyed, only transformed from one form to another. In terms of mechanical energy, this means the sum of an object's kinetic and potential energy remains the same, provided there is no external work done or energy lost.
For the airplane scenario:
- The initial energy when the airplane was at rest is its potential energy at ground level—effectively zero, as it hasn't yet gained height or movement.
- After ascent and acceleration, its total energy is the sum of its gravitational potential energy and kinetic energy.