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Concribe What is the main difference between velocity and speed?

Short Answer

Expert verified
Speed is scalar (no direction); velocity is vector (includes direction).

Step by step solution

01

Define Speed

Speed is a scalar quantity, which means it only has magnitude and no direction. It represents how fast an object is moving, without considering the direction of movement. Speed is calculated as the distance traveled divided by the time taken, expressed with the formula: \( \text{Speed} = \frac{\text{Distance}}{\text{Time}} \).
02

Define Velocity

Velocity is a vector quantity, meaning it has both magnitude and direction. It represents the rate at which an object changes its position. Like speed, velocity is calculated using distance and time, but it also includes the direction of movement. The formula is: \( \text{Velocity} = \frac{\text{Displacement}}{\text{Time}} \), where displacement refers to the change in position in a specific direction.
03

Compare Speed and Velocity

The main difference between speed and velocity is that speed does not include a direction, while velocity does. Speed measures only how fast something is moving, without directional information, while velocity provides information on both the speed and direction of motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scalar and Vector Quantities
When we talk about quantities in physics, they can be broadly classified into two categories: scalar and vector quantities.
Scalar quantities are simple because they only involve magnitude. This means that they tell us how much of something there is, but not in any particular direction. For example, when you talk about the temperature of a day, we simply state it as 25 degrees Celsius. We don't need to specify a direction because it doesn't apply.
Vector quantities, on the other hand, have both magnitude and direction. This makes them slightly more involved but very useful, especially when describing motion. Imagine pushing a box; it's not enough to say "10 Newtons," but rather "10 Newtons to the right." The direction component is essential because it affects how and where the object moves.
  • Remember: Scalars = magnitude only. Examples: mass, speed, time.
  • Vectors = magnitude + direction. Examples: velocity, force, acceleration.
Understanding these differences lays the groundwork for grasping how speed and velocity differ.
Calculation of Speed
Speed is one of the simplest concepts in physics, and it's all about how fast an object is moving without worrying about the direction.
It's a scalar quantity, which means it only involves magnitude. To put it simply, speed tells us how much distance an object covers over time. The widely used formula for speed is:\[\text{Speed} = \frac{\text{Distance}}{\text{Time}}\]
Imagine you're driving down the highway. The speedometer in your car indicates speed in miles per hour or kilometers per hour, which is a direct application of this concept.
Keep in mind that speed is calculated as the total distance traveled over a period of time. It doesn't matter if you're circling back to the starting point multiple times or moving in zig-zags; you're only counting how far you've gone in total and how long it took.
  • Example: Traveling 100 miles in 2 hours means a speed of 50 miles per hour.
  • Speed is always a positive value or zero. It can never be negative because it doesn't have direction.
Calculation of Velocity
Velocity is a vector quantity, which means it includes both speed and direction. It looks at how fast something is moving and where it is headed.
The formula to calculate velocity is slightly different from speed:\[\text{Velocity} = \frac{\text{Displacement}}{\text{Time}}\]
Here, displacement is the change in position of the object, which considers the initial and final position and the shortest path between them in a straight line.
An example can highlight this. If you walk around a track and return to your starting point, your displacement is zero, so your velocity is zero, despite having a positive speed.
Velocity can also be positive, negative, or zero. Negative velocity simply means the object moves in the opposite direction from what we assigned as positive.
  • Remember: Velocity = speed + direction. Focus on "where to," not just "how fast."
  • Velocity provides a more complete understanding of an object's overall movement compared to speed.

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Most popular questions from this chapter

Object 1 starts at \(5.4 \mathrm{~m}\) and moves with a velocity of \(1.3 \mathrm{~m} / \mathrm{s}\). Object 2 starts at \(8.1 \mathrm{~m}\) and moves with a velocity of \(-2.2 \mathrm{~m} / \mathrm{s}\). The two objects are moving directly toward one another. (a) At what time do the objects collide? (b) What is the position of the objects when they collide?

On your cousin's wedding day you leave for the church \(30.0 \mathrm{~min}\) before the ceremony is to begin, which should leave plenty of time since the church is only \(17.0 \mathrm{~km}\) away. On the way, however, you have to make an unanticipated stop because of road construction work. As a result, your average speed for the first \(15 \mathrm{~min}\) is only \(12.0 \mathrm{~km} / \mathrm{h}\). What average speed do you need to have on the remainder of the trip to get you to the church on time?

Calculate A golfer putts on the eighteenth green at a distance of \(5.0 \mathrm{~m}\) from the hole. The ball rolls straight, in the positive direction, but overshoots the hole by \(1.2 \mathrm{~m}\). The golfer then putts back to the hole and sinks the putt for par. (a) What is the distance traveled by the ball? (b) What is the displacement of the ball?

Predict \& Explain You drive your car in a straight line at \(15 \mathrm{~m} / \mathrm{s}\) for \(10 \mathrm{~min}\), then at \(25 \mathrm{~m} / \mathrm{s}\) for another \(10 \mathrm{~min}\). (a) Is your average speed for the entire trip more than, less than, or equal to \(20 \mathrm{~m} / \mathrm{s}\) ? (b) Choose the best explanation from the following: A. More time is required to drive the same distance at \(15 \mathrm{~m} / \mathrm{s}\) than at \(25 \mathrm{~m} / \mathrm{s}\). B. Less distance is covered driving at \(25 \mathrm{~m} / \mathrm{s}\) than at \(15 \mathrm{~m} / \mathrm{s}\). C. Equal time is spent driving at \(15 \mathrm{~m} / \mathrm{s}\) and \(25 \mathrm{~m} / \mathrm{s}\).

After a displacement of \(17 \mathrm{~m}\), a train on a straight track is at the position \(x_{\mathrm{f}}=-2.2 \mathrm{~m}\). What was the train's initial position?

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