Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The p0 is a subatomic particle of fleeting existence. Data tables don't usually quote its lifetime. Rather, they quote a "width," meaning energy uncertainty, of about 150MeV. Roughly what is its lifetime?

Short Answer

Expert verified

The lifetime is t2.2×10-24sec.

Step by step solution

01

Given data.

Energy E=150MeV.

02

Uncertainty principle for energy and time.

tEh2

Energy value,

E=150MeV=150×106×1.6×10-19J=240×10-13J

So,

t1.05×10-34240×10-13t2.2×10-24sec

Therefore, a lifetime is requiredt2.2×10-24sec.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Electrons are accelerated through a 20 V potential difference producing a monoenergetic beam. This is directed at a double-slit apparatus of 0.010 mm slit separation. A bank of electron detectors is 10 m beyond the double slit. With slit 1 alone open, 100 electrons per second are detected at all detectors. With slit 2 alone open, 900 electrons per second are detected at all detectors. Now both slits are open.

(a) The first minimum in the electron count occurs at detector X. How far is it from the center of the interference pattern?

(b) How many electrons per second will be detected at the center detector?

(c) How many electrons per second will be detected at detector X?

In Section 4.3, we claim that in analyzing electromagnetic waves, we could handle the fieldsandtogether with complex numbers. Show that if we define an "electromagnetic field"GE+icB, then the two of Maxwell's equations that linkEandB.(4-6c) and(4-6d) , become just one:

Gdl=ictGdA

Electromagnetic waves would have to obey this complex equation. Does this change of approach make EandB/or complex? (Remember how a complex number is defined.)

Question: Analyzing crystal diffraction is intimately tied to the various different geometries in which the atoms can be arranged in three dimensions and upon their differing effectiveness in reflecting waves. To grasp some of the considerations without too much trouble, consider the simple square arrangement of identical atoms shown in the figure. In diagram (a), waves are incident at angle with the crystal face and are detected at the same angle with the atomic plane. In diagram (b), the crystal has been rotated 450 counterclockwise, and waves are now incident upon planes comprising different sets of atoms. If in the orientation of diagram (b), constructive interference is noted only at an angle, θ=40°at what angle(s) will constructive interference be found in the orientation of diagram (a)? (Note: The spacing between atoms is the same in each diagram.)

A 1 fs pulse of laser light would be 0.3μmlong. What is the range of wavelengths in a 0.3Imlong pulse of (approximately)600nmlaser light?

The energy of a particle of massbound by an unusual spring isβ/2m+bx4.

(a) Classically. it can have zero energy. Quantum mechanically, however, though bothx andpare "on average" zero, its energy cannot be zero. Why?

(b) Roughly speaking.Δxis a typical value of the particle's position. Making a reasonable assumption about a typical value of its momentum, find the particle's minimum possible energy.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free