Chapter 8: Q22CQ (page 339)
Question: Huge tables of characteristic X-rays start at lithium. Why not hydrogen or helium?
Short Answer
Answer
X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.
Chapter 8: Q22CQ (page 339)
Question: Huge tables of characteristic X-rays start at lithium. Why not hydrogen or helium?
Answer
X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.
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Get started for freeAssume that the spin-orbit interaction is not overwhelmed by an external magnetic field what isthe minimum angle the total angular momentum vector may make with the z -axis in a3state of hydrogen?
Determine the rank according to increasing wavelength of and
The Slater determinant is introduced in Exercise 42. Show that if states and of the infinite well are occupied and both spins are up, the Slater determinant yields the antisymmetric multiparticle state:
Here we consider adding two electrons to two "atoms," represented as finite wells. and investigate when the exclusion principle must be taken into account. In the accompanying figure, diagram (a) shows the four lowest-energy wave functions for a double finite well that represents atoms close together. To yield the lowest energy. the first electron added to this system must have wave function and is shared equally between the atoms. The second would al so have function and be equally shared. but it would have to be opposite spin. A third would have function B. Now consider atoms far a part diagram(b) shows, the bumps do not extend much beyond the atoms - they don't overlap-and functions and approach equal energy, as do functions and . Wave functionsandin diagram (b) describe essentially identical shapes in the right well. while being opposite in the left well. Because they are of equal energy. sums or differences ofandare now a valid alternative. An electron in a sum or difference would have the same energy as in either alone, so it would be just as "happy" inrole="math" localid="1659956864834" , or- B. Argue that in this spread-out situation, electrons can be put in one atom without violating the exclusion principle. no matter what states electrons occupy in the other atom.
Exercise 45 refers to state I and II and put their algebraic sum in a simple form. (a) Determine algebraic difference of state I and state II.
(b) Determine whether after swapping spatial state and spin state separately, the algebraic difference of state I and state II is symmetric, antisymmetric or neither, and to check whether the algebraic difference becomes antisymmetric after swapping spatial and spin states both.
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