Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: Huge tables of characteristic X-rays start at lithium. Why not hydrogen or helium?

Short Answer

Expert verified

Answer

X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.

Step by step solution

01

Definition of electron configuration

In atomic physicsandquantum chemistry, the electron configuration is the distribution ofelectronsof anatomormolecule(or other physical structure) inatomicormolecular orbitals.

02

Calculate electronic configuration for hydrogen and helium

Given that the atomic number of hydrogen is Z (H) =1

The atomic number of helium is Z (He) =2

The electron configuration for hydrogen is 1s1

The electron configuration for helium is 1s2

03

Determine the reason

As we see, all of the electrons of hydrogen/helium are on the n = 1 level and this is the only level (shell) present. In order for the X-rays to be created, there must be a hole where an upper electron will fall which is not the case for hydrogen and helium.

Therefore X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume that the spin-orbit interaction is not overwhelmed by an external magnetic field what isthe minimum angle the total angular momentum vector may make with the z -axis in a3state of hydrogen?

Determine the rank according to increasing wavelength ofkฮฑ,kฮฒ andLฮฑ.

The Slater determinant is introduced in Exercise 42. Show that if states nand n'of the infinite well are occupied and both spins are up, the Slater determinant yields the antisymmetric multiparticle state:ฯˆn(x1)โ†‘ฯˆn'(x2)โ†‘โˆ’ฯˆn'(x1)โ†‘ฯˆn(x2)โ†‘

Here we consider adding two electrons to two "atoms," represented as finite wells. and investigate when the exclusion principle must be taken into account. In the accompanying figure, diagram (a) shows the four lowest-energy wave functions for a double finite well that represents atoms close together. To yield the lowest energy. the first electron added to this system must have wave function Aand is shared equally between the atoms. The second would al so have function Aand be equally shared. but it would have to be opposite spin. A third would have function B. Now consider atoms far a part diagram(b) shows, the bumps do not extend much beyond the atoms - they don't overlap-and functions Aand Bapproach equal energy, as do functions Cand D. Wave functionsAandBin diagram (b) describe essentially identical shapes in the right well. while being opposite in the left well. Because they are of equal energy. sums or differences ofandare now a valid alternative. An electron in a sum or difference would have the same energy as in either alone, so it would be just as "happy" inrole="math" localid="1659956864834" A,B,A+B, orA- B. Argue that in this spread-out situation, electrons can be put in one atom without violating the exclusion principle. no matter what states electrons occupy in the other atom.

Exercise 45 refers to state I and II and put their algebraic sum in a simple form. (a) Determine algebraic difference of state I and state II.

(b) Determine whether after swapping spatial state and spin state separately, the algebraic difference of state I and state II is symmetric, antisymmetric or neither, and to check whether the algebraic difference becomes antisymmetric after swapping spatial and spin states both.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free