Question

Question: What if electrons were spin$\frac{\mathbf{3}}{\mathbf{2}}$ instead of spin $\frac{\mathbf{1}}{\mathbf{2}}$. What would be Z for the first noble gas?

Short answer

Answer

The value of z = 4.

Step-by-step solution

Introduction

Assume electrons had spin $\mathit{s}\mathbf{=}\frac{\mathbf{3}}{\mathbf{2}}$ there would be 2s+1=4 possible spin orientations along the given z-axis

Value of z.

It would have z=4.

The first noble gas would have 4 electrons in its 1s state, namely one for each of the possible spin orientations, to have a complete outer shell. It would therefore have z = 4 .