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Question: Lithium is chemically reactive. What if electrons were spin 32instead of spin12. What value of Z would result in an elements reactive in roughly the same way as lithium? What if electrons were instead spin-1?

Short Answer

Expert verified

Answer

The value of Z = 5

Step by step solution

01

Introduction.

If electrons had spin S=32 instead of two possible orientations of the spin measured along a Z-axis, there would be 2s+1 = 4 possible spin orientations, and therefore 4 electrons per in for each orbital. Real lithium with actual spin12 electrons has its filled 2s shell and 1 electron in its 2p shell. The hypothetical atom with spin- 4 electrons would need to have 4 electrons to fill its shell 1s plus the one in its outermost shell, for a total of 5 electrons, to have similar reactivity to real lithium.

02

Value of z.

It would have z = 5.

If the electron had spin 1 it would be a Boson and would not be subject to the exclusion principle. All the electrons of the atom would fall into the . It would not be possible for any such atom, for any atomic number, to have a reactivity similar to lithium.

The value of z would be 5.

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Most popular questions from this chapter

Figureshows the Stern-Gerlach apparatus. It reveals that spin-12particles have just two possible spin states. Assume that when these two beams are separated inside the channel (though still near its centreline). we can choose to block one or the other for study. Now a second such apparatus is added after the first. Their channels are aligned. But the second one is rotated about the-axis by an angle \(\phi\) from the first. Suppose we block the spin-down beam in the first apparatus, allowing only the spin-up beam into the second. There is no wave function for spin. but we can still talk of a probability amplitude, which we square to give a probability. After the first apparatus' spin-up beam passes through the second apparatus, the probability amplitude iscos(ฯ•/2)โ†‘2nd+sin(ฯ•/2)โ†“2ndwhere the arrows indicate the two possible findings for spin in the second apparatus.

(a) What is the probability of finding the particle spin up in the second apparatus? Of finding it spin down? Argue that these probabilities make sense individually for representative values ofฯ•and their sum is also sensible.

(b) By contrasting this spin probability amplitude with a spatial probability amplitude. Such asฯˆ(x)=Aeโˆ’te2. Argue that although the arbitrariness ofฯ•gives the spin cases an infinite number of solves. it is still justified to refer to it as a "two-state system," while the spatial case is an infinite-state system.

To investigate the claim that lowerimplies lower f energy. consider a simple case: lithium. which has twon=1electrons and alonen=2valence electron.

(a)First find the approximate orbit radius, in terms ofa0. of ann=1electron orbiting three protons. (Refer to Section 7.8.)

(b) Assuming then=1electrons shield/cancel out two of the protons in lithium's nucleus, the orbit radius of ann=2electron orbiting a net charge of just+e.

(c) Argue that lithium's valence electron should certainly have lower energy in a 25 state than in a2pstale. (Refer Figure 7.15.)

Question: As indicated to remove one of the heliumโ€™s electrons requires24.6eV of energy when orbiting -24.6eV? Why or why not?

Two particles in a box have a total energy 5ฯ€2โ„2/2mL2.

(a) Which states are occupied?

(b) Make a sketch ofP5(x1,x2)versusx1for points along the linex2=x1.

(c) Make a similar sketch ofPA(x1,x2).

(d) Repeat parts (b) and (c) but for points on the linex2=Lโˆ’x1

Determine the electronic configuration for phosphorus, germanium and cesium.

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