Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: A good electron thief needs a trap at low energy to entice its prey. A poor electron shepherd will have at least some of its flock dangling out at high energy, consider row 2 and 5 in the periodic table. Why should fluorine, in row 2, is less reactive than rubidium, in row 5?

Short Answer

Expert verified

Answer

The electronegativity of fluorine is larger than that of iodine atom and hence fluorine can attract electrons easily from other atoms to form stable chemical bonds. That is why fluorine is more reactive than iodine.

Step by step solution

01

Introduction

The energy required to remove an electron from the outermost orbit of an atom is called the ionization energy of that atom. If the ionization energy of an atom is low then it is easy to remove an electron from its outermost orbit and hence the atom is more reactive.

The electronegativity of an atom depends both on the atomic number and the distance of the valence electrons from the nucleus of an atom. If the electronegativity of an atom is more, it has more tendency to attract an electron towards itself and hence the atom is more reactive.

02

Role of lithium and rubidium

The role of lithium and rubidium is to "give up" an electron. Hence, they are more reactive if they have low ionization energy. The valence electrons in lithium are closer to the nucleus compared that in rubidium atom. Therefore, the ionization energy of rubidium is less compared to that of lithium. That means, it is harder to remove an electron from lithium compared to that of rubidium. Hence rubidium is more reactive than lithium.

03

Role of fluorine and iodine

The role of fluorine and iodine is to "seize" an electron. Hence they are more reactive if they are more electronegative. The size of the fluorine atom is much smaller than the iodine atom. Thus, the outermost electron in iodine is far from the nucleus compared to that in the Fluorine atom. Therefore electronegativity of fluorine is larger than that of the iodine atom and hence fluorine can attract electrons easily from other atoms to form stable chemical bonds. That is why fluorine is more reactive than iodine.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Compare and contrast the angular momentum and magnetic moment related to orbital motion with those that are intrinsic.

Question: Huge tables of characteristic X-rays start at lithium. Why not hydrogen or helium?

Repeat example 8.6 but assume that the upper state is the 2p12rather than the2p32

Figureshows the Stern-Gerlach apparatus. It reveals that spin-12particles have just two possible spin states. Assume that when these two beams are separated inside the channel (though still near its centreline). we can choose to block one or the other for study. Now a second such apparatus is added after the first. Their channels are aligned. But the second one is rotated about the-axis by an angle \(\phi\) from the first. Suppose we block the spin-down beam in the first apparatus, allowing only the spin-up beam into the second. There is no wave function for spin. but we can still talk of a probability amplitude, which we square to give a probability. After the first apparatus' spin-up beam passes through the second apparatus, the probability amplitude iscos(ฯ•/2)โ†‘2nd+sin(ฯ•/2)โ†“2ndwhere the arrows indicate the two possible findings for spin in the second apparatus.

(a) What is the probability of finding the particle spin up in the second apparatus? Of finding it spin down? Argue that these probabilities make sense individually for representative values ofฯ•and their sum is also sensible.

(b) By contrasting this spin probability amplitude with a spatial probability amplitude. Such asฯˆ(x)=Aeโˆ’te2. Argue that although the arbitrariness ofฯ•gives the spin cases an infinite number of solves. it is still justified to refer to it as a "two-state system," while the spatial case is an infinite-state system.

Is intrinsic angular momentum "real" angular momentum? The famous Einstein-de Haas effect demonstrates it. Although it actually requires rather involved techniques and high precision, consider a simplified case. Suppose you have a cylinder 2cmin diameter hanging motionless from a thread connected at the very center of its circular top. A representative atom in the cylinder has atomic mass 60 and one electron free to respond to an external field. Initially, spin orientations are as likely to be up as down, but a strong magnetic field in the upward direction is suddenly applied, causing the magnetic moments of all free electrons to align with the field.

(a) Viewed from above, which way would the cylinder rotate?

(b) What would be the initial rotation rate?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free