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Question: In nature, lithium exists in two isotopes: lithium-6, with three neutrons in its nucleus, and lithium-7, with four as individual atoms, would these behave as Bosons or as Fermions? Might a gas of either behave as a gas of Bosons? Explain.

Short Answer

Expert verified

Answer:

Pairing up of valence electrons of each lithium-6 atom with another atom in lithium-6 gas will result in the integral spin of the system and will lead to Bosonic behavior.

Step by step solution

01

A concept:

Particles that carry forces, are known as "bosons."

In particle physics, a boson is a subatomic particle whose spin quantum number has an integer value. Bosons form one of the two basic classes of subatomic particles, the other being fermions, which have an odd half-number spin.

Natural lithium consists of two isotopes: Lithium-7 and Lithium-6 . Lithium-6 has 3 protons (as it must if it is to be the element Lithium) but only 3 neutrons, so it has a mass number of 6.

02

Explanation of Bosons:

As individual atoms, lithium-6 will behave as fermion; lithium- 7 will behave as a boson. Lithium-6 gas can behave as a boson. The lithium-6 atom has only one electron in its outermost orbit (2s). Hence, if it pairs with the other Lithium-6 atom-forming gas, the gas will behave as a boson.

03

Pairing lithium-6 and lithium-7:

As individual atoms, lithium-6 has a total of 9 particles (protons, electrons, and neutrons 3 each). Hence, there is a net half-integral spin that results in Fermion behavior. A particle with a half-integral spin obeys Pauli's exclusion principle and each one occupies a separate state. Whereas in lithium- 7 the excess one neutron results in a net integral spin of the isotope and behave as a boson.

Pairing up the valence electrons of each lithium-6 atom with other atoms, an atom in lithium-6 gas will result in an integral spin of the system and will lead to Bosonic behavior.

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Most popular questions from this chapter

Two particles in a box occupy the n=1andn'=2individual-particle states. Given that the normalization constant is the same as in Example8.2(see Exercise 36), calculate for both the symmetric and antisymmetric states the probability that both particles would be found in the left side of the box (i.e., between 0 and13L)?

What is the angle between the spins in a triplet state?

Your friends ask: โ€œWhy is there an exclusion principle?โ€ Explain in the simplest terms.

Show that unless l=s, L and S cannot be exactly opposite: that is, show that at its minimum possible value. Forwhich j=l-s. The magnitude of the total angular momentum is strictly greater than the difference L-Sbetween the magnitudes of the orbital and intrinsic angular momentum vectors.

A Simple Model: The multielectron atom is unsolvable, but simple models go a long way. Section7.8gives energies and orbit radii forone-electron/hydrogenlike atoms. Let us see how useful these are by considering lithium.

(a) Treat one of lithium'sn=1electrons as a single electron in a one-electron atom ofrole="math" localid="1659948261120" Z=3. Find the energy and orbit radius.

(b) The othern=1electron being in the same spatial state. must have the same energy and radius, but we must account for the repulsion between these electrons. Assuming they are roughly one orbit diameter apart, what repulsive energy would they share, and if each claims half this energy. what would be the energies of these two electrons?

(c) Approximately what charge does lithium's lone valence electron orbit, and what radius and energy would it have?

(d) Is in reasonable to dismiss the role of then=1electrons in chemical reactions?

(e) The actual energies of lithium's electrons are about-98eV(twice, of course) and-5.4eV. How good is the model?

(f) Why should the model's prediction for the valence electron's energy differ in the direction it does from the actual value?

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