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Through a window in Carl's spaceship, passing al 0.5c, you watch Carl doing an important physics calculation. By your watch it takes him 1 min. How much time did Carl spend on his calculation?

Short Answer

Expert verified

The time spends by Carl in spaceship for calculation is0.87min.

Step by step solution

01

Identification of given information

The given data can be listed below as:

  • The speed of spaceship is, v=0.5c.
  • The time measured by watch is, .
02

Usage of time dilation concept

The problem is based on the concept of time dilation. The spaceship for this problem is moving at half the speed of light.

03

Determination of the formula of the time dilation for spaceship

The formula to calculate the time dilation for spaceship is:

t2=t11-v2c2

04

Determination of the time dilation for spaceship

Substitute all the values in the above equation.

1min=t11-(0.5c)2c2t1=0.87min

Therefore, the time spend by Carl in spaceship for calculation is0.87min.

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Most popular questions from this chapter

Question: A 1 kg object moves at 0.8c relative to Earth.

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