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Using the functions given in Table 7.4, verify that for the more circular electron orbit in hydrogen (i.e.,l=n-1), the radial probability is of the form

P(r)r2ne-2r/nao

Show that the most probable radius is given by

rmostprobable=n2ao

Short Answer

Expert verified

The most probable radius isr=n2a0.

Step by step solution

01

 Given data

The radial function for l=n-1is,

role="math" localid="1659182273339" Rn,n-1rn-1e-r/(nao)

02

 Concept

The most probable radius is the radius of the orbit in which the probability of finding the electron is maximum.

The probability density is

P(r)=r2R2n,n-1

03

 Solution

P(r)=r2R2n,n-1=r2rn-1e-r/(nao)=r2r2n-2e-r/(nao)=r2ne-r/(nao)

To find the most probable location, take the derivative of the probability density,

dPrdr=ddrr2ne-2rlna°=2nr2n-1e-2rlna°+r2n-2na°e-2rlna°=e-2rlna°r2n-12n+-2rna°

For the most probable location, the derivative should be equal to zero.

role="math" localid="1659182748704" =e-2rlna°r2n-12n+-2rna°

Hence,

2n+-2rna°=0r=n2a°

The most probable radius is r=n2a°.

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